输出Tuple <string，string> List作为JSON对象</string，string>

Question

我应该输出JSON中的设置列表，我从数据库中获取并存储在Tuple<string, string>中。

我能够打印它，但它不会显示它应该：

[{
    "Item1": "setting1Name",
    "Item2": "setting1Value"
 }, {
    "Item1": "testt",
    "Item2": "testt"
 }, {...
 }]

输出应为：

[
  {"setting1Name":"setting1Value"},
  {"setting2Name":"setting2Value"},{...}
]

如何将元组序列化为JSON？

控制器：

[GET("Settings")]
public async Task<ActionResult> Settings(string userKey)
{             
    if ((await UserManager.FindByIdAsync(userKey)) == null)
        return new HttpUnauthorizedResult();                        

    List<Tuple<string, string>> settings = new List<Tuple<string, string>>();

    var userSettings = settingRepository.Get(new Guid(userKey));

    for (int i = 0; i < userSettings.Count; i++)
    {
        var tuple = Tuple.Create<string, string>(
            userSettings[i].Name.ToString(),
            userSettings[i].Value.ToString()
            );
        settings.Add(tuple);                
    }                      
        return Json(settings,JsonRequestBehavior.AllowGet);
}

数据库存储库方法：

public List<Setting> Get(Guid userId)
{
    return _context.Settings.Where(s => s.UserId == userId).ToList();
}

Answer 1

你可以玩这样的东西

替换此行

return Json(settings,JsonRequestBehavior.AllowGet);

使用

var dict = new Dictionary<string, string>();
settings.ForEach(a => dict.Add(a.Item1, a.Item2));           
return Json(new List<Dictionary<string, string>>{dict}, 
       JsonRequestBehavior.AllowGet);