Question

我是新手，并且在使用这个sql函数时遇到了一些困难。我试图在sql中创建一个函数，但它不起作用，它接受@A int和@B int的参数返回＆＃34; bit＆＃34;的数据类型。试图检查表C和D中是否存在@A int或@B int。如果存在返回值1，否则为0

这是我的代码

CREATE FUNCTION fn_exist(
@A int, @B int
)
RETURNS bit
as
begin

Declare @year int
    select @year as [year]
    case [YEAR] when @A in (C or D)
    or @B in (C and D)
    then 1 else 0
    from dbo.mytable
    return @year 

end

Answer 1

试试这个：

Declare @value as bit

select @value =
case
    when exists(
      select 1
      from dbo.mytable
      where (@A = C OR @A = D) OR (@B = C OR @B = D)
    )
    then 1 else 0
end

return @value

Answer 2

看看你的代码示例我认为你想要这样的东西：

DECLARE @value AS BIT
IF EXISTS(
   SELECT NULL
   FROM dbo.mytable
   WHERE (@A = C OR @A = D) OR (@B = C OR @B = D)
) 
   SET @value = CAST(1 As bit)
ELSE 
   SET @value = CAST(0 As bit)

RETURN @value

sql函数检查表的任一列中是否存在任何值

2 个答案: