Question

我有一组数字，例如：

a = [1,2,3,4,5,6,7,8,9,10,11]

常数：

TITLES = ['a', 'b', 'c', 'd']

当我迭代a时，我希望得到每个项目的标题：

- iterating over a, first item (1) get title 'a'
- iterating over a, first item (2) get title 'b'
- iterating over a, first item (3) get title 'c'
- iterating over a, first item (4) get title 'd'
- iterating over a, first item (5) get title 'a'
- iterating over a, first item (6) get title 'b'

所以当我从头开始跑过头衔时，这就是我现在所拥有的：

a.each_with_index do |m, i|
  if TITLES[i].nil?
    title = TITLES[(i - TITLES.length)]
  else
    title = TITLES[i]
  end
end

但是这不起作用，遗憾的是我为nil的最后一项获得了a标题。我怎样才能做到这一点？

Answer 1

您可以使用zip和cycle方法，如下所示：

a.zip(TITLES.cycle).each do |x, title|
  p [x, title]
end

# Output:
# [1, "a"]
# [2, "b"]
# [3, "c"]
# [4, "d"]
# [5, "a"]
# ...

Answer 2

使用#each_with_index

这种明显的方法

a.each_with_index do |x, i|
  p [x, TITLES[i % TITLES.length]]
end

或者，尝试这样的事情......

a.zip(TITLES*3).each do |x, y|
  p [x, y]
end

Answer 3

怎么样：

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
TITLES = ['a', 'b', 'c', 'd']

t_length = TITLES.length

a.each_with_index do |item, index|
  t_index = index % t_length
  title = TITLES[t_index]
  puts "item: #{item} - title: #{title}"
end

Answer 4

a = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
TITLES = ['a', 'b', 'c', 'd']

TITLES = TITLES + TITLES + TITLES

 (a.zip TITLES).each do |p, q|
    puts "======#{p}==#{q}======"
 end

如何从另一个循环连续循环数组值？

4 个答案: