我想知道是否有人有解决方案。 我不断收到错误，我的程序因OCR GCSE计算的配方任务而无法正常工作。我已设法在外部文本文件中创建添加配方，并搜索现有配方。
我遇到的问题是为配方的不同人数重新计算新数量（所有数字数据）。我使用的是Python版本3。
我的修订计划部分如下。 （我违反了1人的所有食谱）因此更容易重新计算新数量。
我的代码如下。**
我提前感谢您的帮助。
import os
def modify():
#create a boolean variable to use as a flag
found = False
#Get the search value and the new recipe information.
search = input ("Enter a recipe name to search for: ")
new_number_of_people =input("Enter the new number of people to serve (default is 1):")
#open the original recipeList.txt file.
recipeList_file=open("recipeList.txt", "r")
#open the temporary file.
temp_file = open("temp.txt", "w")
#Read the first record's recipe name field
recipe = recipeList_file.readline()
#Read the rest of the file.
while recipe != "":
#Read the recipe item,quantity, units and number of people.
ingredient1 = str(recipeList_file.readline())
quantity1 =float(recipeList_file.readline())
units1 = str (recipeList_file.readline())
ingredient2 = str(recipeList_file.readline())
quantity2 =float(recipeList_file.readline())
units2 = str (recipeList_file.readline())
ingredient3 = str(recipeList_file.readline())
quantity3 =float(recipeList_file.readline())
units3 = str (recipeList_file.readline())
number_of_people = float(recipeList_file.readline())
recipe = recipe.rstrip("\n")
#write a new record with the temp file
if recipe == search:
#write the modified record to the temp file.
temp_file.write(recipe + "\n")
temp_file.write(ingredient1+ "\n")
temp_file.write((quantity1*input(new_number_of_people)) + "\n")
temp_file.write(units1 + "\n")
temp_file.write(ingredient2+ "\n")
temp_file.write((quantity2*input(new_number_of_people)) + "\n")
temp_file.write(units2 + "\n")
temp_file.write(ingredient3+ "\n")
temp_file.write((quantity3*input(new_number_of_people)) + "\n")
temp_file.write(units3 + "\n")
temp_file.write((new_number_of_people) + "\n")
#Set the found flag to True.
found = True
else:
#write the original record to the temp file.
#write the modified record to the temp file.
temp_file.write(recipe + "\n")
temp_file.write(ingredient1+ "\n")
temp_file.write((quantity1*input(new_number_of_people)) + "\n")
temp_file.write(units1 + "\n")
temp_file.write(ingredient2+ "\n")
temp_file.write((quantity2*input(new_number_of_people)) + "\n")
temp_file.write(units2 + "\n")
temp_file.write(ingredient3+ "\n")
temp_file.write((quantity3*input(new_number_of_people)) + "\n")
temp_file.write(units3 + "\n")
temp_file.write((new_number_of_people) + "\n")
#Read the next recipe
ingredient1 = str(recipeList_file.readline())
quantity1 = float(recipeList_file.readline())
units1 = str (recipeList_file.readline())
ingredient2 = str(recipeList_file.readline())
quantity2 = float(recipeList_file.readline())
units2 = str (recipeList_file.readline())
ingredient3 = str(recipeList_file.readline())
quantity3 = float(recipeList_file.readline())
units3 = str (recipeList_file.readline())
number_of_people = float(recipeList_file.readline())
#Close the Recipe file and the temporary file.
recipeList_file.close()
temp_file.close()
#Delete the original recipeList.txt file.
os.remove ("recipeList.txt")
#Rename the temporary file.
os.rename("temp.txt", "recipeList.txt")
#if the search was not found in the file display message
if found:
print ("The file has been updated.")
else:
print ("That recipe was not found in the file")
#call the main function.
modify()
recipeList.txt格式：
Cake
Flour
20
grams
Eggs
2
Number
Butter
2
spoons
1
答案 0 :(得分：0)
输入文件的格式不是最好的。我会更好地连续每个食谱，每个数据都有一个分隔符（逗号），一个csv格式。
但是输入是以那种格式给出的......
首先，为每项任务制定一项功能是一个好习惯。因此，我认为有3个任务：
question()功能。说明：
向用户询问输入数据，然后返回元组。
modify()功能。说明：
打开文件输入后，我读取（）所有文件，并使用＆＃39; \ n＆＃39;分割每一行。分隔器。这会生成一个列表，其中包含文件每行的内容。
由于配方名称在文件中是唯一的，我想在调用函数时访问确定的配方，我认为最好使用字典名称 配方是关键，其他数据（我把它放在一个列表中）是值。是， dict的值可以是Python中的任何对象，因此我使用列表。我定义了一个空白字典以添加食谱。
一个配方有12个数据（包括末尾的空行），所以使用zip(*[iter(recipeList)]*12)我创建了12个元素的元组，我可以使用for语句进行迭代。
元组的0索引是我用作键的配方的名称。其余的元组
（使用从第二个元素到结尾的切片[1:]）在列表中转换的是字典对的值。为何列出清单？因为元组在Python中是不可变的。
然后我迭代列表（从第二个元素步骤3个元素;数量）用产品数量更新产品的值。最后，我用人数更新了列表的第十项。
此函数返回更新字典。
save()功能。
尝试自己编写代码。您只需要迭代字典（嵌套列表）并将一行中的每个数据写入配方的新文件。 （不要忘记写每个字典对的密钥，是配方的名称）。
import os
def modify(recipe_name, number):
recipeList_file = open('recipeList.txt', 'r', newline= None)
recipeList = recipeList_file.read().split('\n')
recipeDict = {}
for i in zip(*[iter(recipeList)]*12):
print(i) # For debugging purpose
recipeDict[i[0]] = list(i[1:])
print(recipeDict.items()) # For debugging purpose
for j in range(1, 10, 3):
recipeDict[recipe_name][j] = str(int(recipeDict[recipe_name][j]) * number)
recipeDict[recipe_name][9] = str(number)
print(recipeDict.items()) # For debugging purpose
recipeList_file.close()
return recipeDict
def question():
search = input("Enter a recipe name to search for: ")
new_number_of_people = int(input("Enter the new number of people to serve (default is 1):"))
return search, new_number_of_people
def save(dictionarySave):
pass
# Think yourself.
recipe_to_modify, number_to_modify = question()
new_recipe_dictionary = modify(recipe_to_modify, number_to_modify)
save(new_recipe_dictionary)