Question

我在php中创建xml文件时遇到了这个错误。 cna你能告诉我解决方案

                 error on line 7 at column 374: xmlParseEntityRef: no name


                        header("Content-Type: application/xml; charset=utf-8");

                date_default_timezone_set("Asia/Calcutta");
                $content=$this->view->data=$this->CallModel('posts')->GalleryAndContent();
          $xml = '<?xml version="1.0" encoding="UTF-8" ?>
                            <rss version="2.0">
                            <channel>';                           
          $xml.='<title>Thehansindia</title>
                    <link>http://www.thehansindia.com</link>
                    <description>Newspaper with a difference</description>';   

            foreach($content as $k){
                        $data=strip_tags(stripslashes($k['text_data']),"<p><span><div>");

                        $data=preg_replace("/<([a-z][a-z0-9]*)[^>]*?(\/?)>/i",'<$1$2>', $data);

                         $data=str_replace(array("<div>","</div>","<span>","</span>"),array("<p>","</p>","<p>","</p>"),$data);
                        $data= preg_replace('/<p>\p{Z}*<\/p>/u', '', $data); 
                         $data=str_replace("<p/>"," ",$data);
                        $data= preg_replace('/<p>\p{Z}*<\/p>/u', '', $data);
                            $data=str_replace( '<p>&nbsp;</p>', ' ', $data);
                        $data=str_replace( '&nbsp;', ' ', $data);
                        // $pattern = "/<[^\/>]*>([\s]?)*<\/[^>]*>/"; 
                        // $data= preg_replace($pattern, '', $data);

/

                        $xml.= '<item>';
                        $xml.=" <storyid>".$k['id']."</storyid>"; 
                        $xml.=" <Headline>".$k['title']."</Headline>";
                        //$xml.="<content>".html_entity_decode($data)."</content>";
                        $dom = new DOMDocument;
                        @$dom->loadHTML($data);
                        $xml.="<CONTENT>";
                        foreach ($dom->getElementsByTagName('p') as $tag){
                            if(!empty($tag->nodeValue)){ 


                            $xml.="<p>".$tag->nodeValue."</p>";

                            }
                            }



                        // $xml.="<CONTENT>".$VALUES['text_data']."</CONTENT>";
                            $xml.="</CONTENT>";
                            $xml.= '</item>';

    }


                      $xml.='</channel></rss> '; 
                      echo $xml;

这是我的代码。通过使用这个我在xml页面中显示mysql的内容。那个somany特殊的chrs就是那就是为什么我在那里使用了html_entity_decode。你能告诉我那个解决方案吗

第374行第7行的错误：xmlParseEntityRef：没有名称

0 个答案: