Question

我已成功为tomcat websockets实现了一个简单的echo服务器示例。现在我需要从我的服务器向客户端发送连续消息。我如何实现这一目标？

显示服务器端代码

package org.playjava.websocket;

import java.io.IOException;
import java.nio.ByteBuffer;
import java.nio.CharBuffer;
import javax.servlet.http.HttpServletRequest;
import org.apache.catalina.websocket.MessageInbound;
import org.apache.catalina.websocket.StreamInbound;
import org.apache.catalina.websocket.WebSocketServlet;
import org.apache.catalina.websocket.WsOutbound;

public class SimpleEchoServlet extends WebSocketServlet {

    @Override
    protected StreamInbound createWebSocketInbound(String string, HttpServletRequest hsr) {
        return new SimpleEchoInbound();
    }

    private static final class SimpleEchoInbound extends MessageInbound {

        public SimpleEchoInbound() {
            super();
        }




        @Override
        protected void onBinaryMessage(ByteBuffer message) throws IOException {
            getWsOutbound().writeBinaryMessage(message);
        }

        @Override
        protected void onTextMessage(CharBuffer message) throws IOException {
            getWsOutbound().writeTextMessage(message);
            getWsOutbound().writeTextMessage(message);
            getWsOutbound().writeTextMessage(message);
        }



    }
}

Answer 1

在SimpleEchoInbound的构造函数中启动一个线程，并在该线程中调用getWsOutbound（）。writeTextMessage（）。

顺便说一句，您正在使用Tomcat专有的WebSocket API，该API已在Tomcat 7中弃用，并且已完全在Tomcat 8中删除。您应该切换到完全支持的JSR-356 Java WebSocket API Tomcat 7和Tomcat 8。

Apache Tomcat websockets服务器端消息

1 个答案: