Question

收到以下错误：

<openjpa-2.2.2-r422266:1468616 fatal user error> org.apache.openjpa.persistence.ArgumentException: "com.qbe.asia.ebusiness.admin.intermediary.Intermediary.employees<element:class com.qbe.asia.ebusiness.admin.intermediary.Employee>" declares a column that is not compatible with the expected type "varchar".  Column details:
Full Name: TINT_STAFF.STAFF_ID
Type: blob
Size: 0
Default: null
Not Null: false

中介，JAVA

@Entity
@Table( name = "TINTERMEDIARY" )
public class Intermediary {

    @Id
    @Column(name="INTERMEDIARY_ID")
    private String intermediaryId;

    @ManyToMany
    @JoinTable(name="TINT_STAFF",
        joinColumns = {
                  @JoinColumn(name = "INTERMEDIARY_ID"),
                  @JoinColumn(name = "STAFF_ID")},
        inverseJoinColumns = {
                  @JoinColumn(name = "STAFF_ID""), 
                  @JoinColumn(name = "INTERMEDIARY_ID")})
    private List<Employee> employees;
}

Employee.java

 @Entity
 @Table(name="TSTAFFMEMBER")
 public class Employee {

   @Id
   @Column(name="STAFF_ID")
   private String employeeId;

   @ManyToMany (mappedBy = "employees")
   private List<Intermediary> intermediaries;
 }

TINT_STAFF表

CREATE TABLE TINT_STAFF
(
    INTERMEDIARY_ID CHAR(19) NOT NULL,
    STAFF_ID CHAR(19) NOT NULL,
    PRIMARY KEY ( INTERMEDIARY_ID, STAFF_ID )
);

所有id字段在其他表中也是CHAR（19）。

没有关联映射就像魅力一样，但是只要我通过TINT_STAFF表添加ManyToMany，就会说列是blob ..但事实并非如此。为什么呢？

更新：

测试失败

@Autowired
IntermediaryDaoJpaImpl dao; //this works fine

@Test
public void getIntermediariesTest() {
    List<Intermediary> intermediaries = dao.getIntermediaries();
    for(Intermediary intermediary : intermediaries) {
        System.out.println("Employees: "+intermediary.getEmployees());
        assert intermediary.getEmployees() != null; 
    }
}

道：

@PersistenceContext
private EntityManager entityManager; //this works

public List<Intermediary> getIntermediaries() {
    Query query = entityManager.createQuery("select o FROM Intermediary o");
    return query.getResultList();
}

的persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
             version="2.0">
    <persistence-unit name="manager1" transaction-type="RESOURCE_LOCAL">
        <provider>org.apache.openjpa.persistence.PersistenceProviderImpl</provider>
        <jta-data-source>java:comp/env/jdbc/Datasource</jta-data-source>
        <class>com.qbe.asia.ebusiness.admin.intermediary.Intermediary</class>
        <class>com.qbe.asia.ebusiness.admin.intermediary.Employee</class>
        <properties>
            <property name="openjpa.jdbc.DBDictionary" value="db2(batchLimit=0)"/>
            <property name="openjpa.Log" value="SQL=TRACE" />
            <property name="openjpa.ConnectionFactoryProperties" value="PrettyPrint=true, PrettyPrintLineLength=72" />
            <property name="openjpa.RuntimeUnenhancedClasses" value="supported" />
        </properties>
    </persistence-unit>
</persistence>

Answer 1

将@JoinTable注释更改为：

@JoinTable(name="TINT_STAFF",
    joinColumns = @JoinColumn(name = "INTERMEDIARY_ID"),
    inverseJoinColumns = @JoinColumn(name = "STAFF_ID""))

可能你想做那样的事。

DB2，openjpa，@ ManyToMany：错误＆＃34;期望的类型varchar但列类型是blob＆＃34;

1 个答案: