我正在尝试制作Java桌面应用程序,我想让自动图像洗牌我能够做到这一点,但问题是它不是洗牌我给的所有图像我想要洗牌所有图像 我怎么能实现这个
以下是我找到的一些代码here:
/**
* @see https://stackoverflow.com/a/22423511/230513
* @see https://stackoverflow.com/a/12228640/230513
*/
public class ImageShuffle extends JPanel {
private List<Icon> list = new ArrayList<Icon>();
private JLabel label = new JLabel();
private Timer timer = new Timer(1000, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
update();
}
});
public ImageShuffle() {
this.setLayout(new GridLayout(1, 0));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\e.jpg"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\d.jpg"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\yellow.png"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\f.jpg"));
// list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\yellow.jpg"));
//label.setIcon(UIManager.getIcon("OptionPane.informationIcon"));
timer.start();
}
private void update() {
Random r=new Random();
int i1=(r.nextInt(3) +1);
label.setIcon(list.get(i1));
}
private void display() {
JFrame f = new JFrame("ImageShuffle");
f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.add(this);
f.add(label);
f.pack();
f.setLocationRelativeTo(null);
f.setVisible(true);
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
new ImageShuffle().display();
}
});
}
}
提前致谢
答案 0 :(得分:2)
首先创建一个混洗列表...
private List<Icon> list = new ArrayList<Icon>();
private List<Icon> shuffled;
//...
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\e.jpg"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\d.jpg"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\yellow.png"));
list.add(new ImageIcon("E:\\SOFTWARE\\TrainPIS\\res\\drawable\\f.jpg"));
shuffled = new ArrayList<Icon>();
update();
每次你的计时器滴答并调用actionPerformed
时,弹出shuffled
列表的第一个元素,直到没有剩下......
if (shuffled.isEmpty()) {
shuffled.addAll(list);
// Prevent the current image from been selected next...
shuffled.remove(label.getIcon());
Collections.shuffle(shuffled);
}
Icon icon = shuffled.remove(0);
label.setIcon(icon);
这将消除允许连续多次显示图像的可能性。无论如何,你的随机值计算应该更像int i1 = (r.nextInt(list.size()));
...
备注:强>
ImageShuffle
不需要从JPanel
延伸,您不需要添加任何内容。这意味着你可以摆脱this.setLayout(new GridLayout(1, 0));
和f.add(this);
,程序应该仍然运行