Question

我有三个表格jobs，categories和job_categories与以下结构相似：

 **jobs**

 id title desc


**categories**
id name

**job_categories**
id job_id category_id

所以我想检索属于特定类别的所有作业。为此，我在view()

中写了一个动作CategoriesController.php

function view($category_id =  NULL)
    {
          if($category_id != NULL)
          {
              $conditions['JobCategory']['category_id'] = $category_id; 
              $all_jobs = $this->Job->find('all',array('conditions' => $conditions));
              $this->set('all_jobs',$all_jobs);
          }
    }

并添加了$hasMany到Category.php模型：

class Category extends AppModel {

    var $name = 'Category';
    var $hasMany = array('JobCategory');
}

但是当我查看视图时，它显示错误：

Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'JobCategory' in 'where clause'及其生成的查询：

选择Job。id，Job。job_title，Job。job_description， Job。job_skills，Job。contact_number，Job。contact_email， Job。qualification_id，Job。experience，Job。categories， Job。remarks，Job。support_image，Job。freshers_apply， Job。added_on，Job。status，Qualification。id， Qualification。name FROM cakead。jobs AS Job LEFT JOIN cakead。qualifications AS Qualification ON （Job。qualification_id = Qualification。id）WHERE JobCategory = （ '1'）

Answer 1

试试这个

// AppModel.php

public $actAs = array('Containable');

// Category.php

class Category extends AppModel {

    var $name = 'Category';
    var $hasAndBelongsTo = array('Category');
}

// CategoriesController.php

function view($category_id =  NULL)
    {
          if($category_id != NULL)
          {
              $conditions['Category']['id'] = $category_id; 
              $all_jobs = $this->Category->find('all',array('conditions' => $conditions));
              $this->set('all_jobs',$all_jobs);
          }
    }

Cakephp有很多没有JOINing表

1 个答案: