Question

正如我之前所说（RGB to Philips Hue (HSB)），我仍然没有放弃将简单的RGB值转换为飞利浦Hue接受的价值的希望。

适用于iPhone和Android的官方应用程序允许您从随机照片中选择颜色，而Hue将相应地进行自我调整。所以必须有某种公式。

但是这一次，我想我刚刚在网上找到了这篇有趣的文章：

https://github.com/PhilipsHue/PhilipsHueSDK-iOS-OSX/blob/master/ApplicationDesignNotes/RGB%20to%20xy%20Color%20conversion.md

我一直试图将他的解释转换为Java语言，但我没有得到理想的结果。谁知道出了什么问题？

有关我使用飞利浦Hue灯泡的记录。

public static List<Double> getRGBtoXY(Color c) {
        // For the hue bulb the corners of the triangle are:
        // -Red: 0.675, 0.322
        // -Green: 0.4091, 0.518
        // -Blue: 0.167, 0.04
        double[] normalizedToOne = new double[3];
        float cred, cgreen, cblue;
        cred = c.getRed();
        cgreen = c.getGreen();
        cblue = c.getBlue();
        normalizedToOne[0] = (cred / 255);
        normalizedToOne[1] = (cgreen / 255);
        normalizedToOne[2] = (cblue / 255);
        float red, green, blue;

        // Make red more vivid
        if (normalizedToOne[0] > 0.04045) {
            red = (float) Math.pow(
                    (normalizedToOne[0] + 0.055) / (1.0 + 0.055), 2.4);
        } else {
            red = (float) (normalizedToOne[0] / 12.92);
        }

        // Make green more vivid
        if (normalizedToOne[1] > 0.04045) {
            green = (float) Math.pow((normalizedToOne[1] + 0.055)
                    / (1.0 + 0.055), 2.4);
        } else {
            green = (float) (normalizedToOne[1] / 12.92);
        }

        // Make blue more vivid
        if (normalizedToOne[2] > 0.04045) {
            blue = (float) Math.pow((normalizedToOne[2] + 0.055)
                    / (1.0 + 0.055), 2.4);
        } else {
            blue = (float) (normalizedToOne[2] / 12.92);
        }

        float X = (float) (red * 0.649926 + green * 0.103455 + blue * 0.197109);
        float Y = (float) (red * 0.234327 + green * 0.743075 + blue + 0.022598);
        float Z = (float) (red * 0.0000000 + green * 0.053077 + blue * 1.035763);

        float x = X / (X + Y + Z);
        float y = Y / (X + Y + Z);

        double[] xy = new double[2];
        xy[0] = x;
        xy[1] = y;
        List<Double> xyAsList = Doubles.asList(xy);
        return xyAsList;
    }

这不是重复的吗？请阅读引用的问题以完全理解。这是转换为XY的问题。引用的问题是关于将RGB转换为HSB。这怎么可能一样？！？！

Answer 1

发现一个小错误：

float Y = (float) (red * 0.234327 + green * 0.743075 + blue + 0.022598);

应该是

float Y = (float) (red * 0.234327 + green * 0.743075 + blue * 0.022598);

RGB到CIE颜色转换

1 个答案: