下面是我的代码:我已经定义了一个具有姓氏,名字和分数的学生类,以及获取和设置方法,如下所示。
在main中我创建了一个学生对象数组。数组必须从命令行获取其元素值。我不知道如何在foreach循环中使用scanner来将命令行的输入存储到数组中。
主要作业是读取多个学生的3个条目,并根据姓氏显示排序的输出。
package student;
abstract class Student implements Comparable{
private String lastname;
private String firstname;
private int score;
public Student( ){
}
public void setLastname(String lastname)
{
this.lastname= lastname;
}
public void setFirstName(String firstname)
{
this.firstname = firstname;
}
public void setScore(int score)
{
this.score=score;
}
public String getLastName()
{
return lastname;
}
public String getFirstName()
{
return firstname;
}
public int getScore()
{
return score;
}
public int CompareTo(Object o)
{
Student s = (Student) o;
int comparison;
final int EQUAL = 0;
comparison=this.lastname.compareTo(s.lastname);
if(comparison != EQUAL)
return comparison;
else comparison = this.firstname.compareTo(s.firstname);
if(comparison!= EQUAL)
return comparison;
return EQUAL;
}
}
package student;
import java.util.Scanner;
import java.util.Arrays;
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) {
// TODO code application logic here
System.out.println("Welcome to the Students Score Application");
System.out.print("Enter the number of Students: ");
Scanner sc = new Scanner(System.in);
int num_Students = sc.nextInt();
Student[] stu = new Student[num_Students];
String lname ="";
for(Student s: stu)
{
int count = 1;
System.out.print("Student " + count + " Last Name: ");
//if(sc.hasNext())
// lname = sc.nextLine();
// s[lname];
System.out.println("Student " + count + "First Name: ");
// if(sc.hasNext())
// s.setFirstName(sc.nextLine());
System.out.println("Student " + count + "Score: ");
// if(sc.hasNextInt())
// s.setScore(sc.nextInt());
count++;
sc.nextLine();
}
Arrays.sort(stu);
for (Student s: stu)
System.out.println(s.getLastName()+ " , " + s.getFirstName()+ ":" + s.getScore());
}
}
答案 0 :(得分:0)
抱歉,但我不明白这一点:
Student[] stu = new Student[num_Students];
String lname ="";
for(Student s: stu)
{
...
}
据我所知,创建一个学生数组不会为数组的每个单元格创建一个新的学生。所以你循环不会运行。
答案 1 :(得分:0)
如果要扫描命令行参数,则需要从main扫描args[]
字段。
...并从标题回答你的问题:
public static void main(String[] args) {
String arguments = "Anton Bert Charly";
Scanner scanner = new Scanner(arguments);
String[] s = new String[3];
// Scan
for (int i = 0; i < s.length; i++) {
if (scanner.hasNext()) {
s[i] = scanner.next();
}
}
// Print out
for (int i = 0; i < s.length; i++) {
System.out.println(s[i]);
}
}
将扫描字符串arguments
并打印出来:
Anton
Bert
Charly
(虽然它没有使用foreach循环)
关心迈克 [; - )
答案 2 :(得分:0)
我认为你混合了系统输入和命令行。第二个意味着您将学生作为程序参数传递给程序,例如。
java Student 2 Paul Thomson 5 Mike Keig 6
要解析这样的命令行,您需要以下代码:
public static void main(String[] args) {
int num_Students = Integer.parseInt(args[0]); //Really not necessary
List<Student> stu = new LinkedList<Student>();
for (int i = 1; i < args.length; i += 3) {
Student student = new Student();
student.setFirstName(args[i]);
student.setLastname(args[i + 1]);
student.setScore(Integer.parseInt(args[i + 2]));
stu.add(student);
}
}
如果您更喜欢从系统输入中读取学生,则可以使用Scaner课程。通常,如果删除注释,创建Studend inctance并从Studend类中删除摘要,则代码应该有效。
答案 3 :(得分:0)
非常感谢您的反馈。这是我第一次尝试在网上发布一个问题,你会让我意识到它有效:)。
我意识到我的错误在哪里。它是在我的方法compareTo()的声明中,除了main中的一些更改之外,我使用“C”代替“c”进行compareTo。在这里:
驱动程序文件: import java.util.Scanner; import java.util.Arrays;
public class Main {
public static void main(String[] args) {
System.out.println("Welcome to the Students Score Application");
Scanner sc = new Scanner(System.in);
System.out.print("Enter the number of Students: ");
int num_Students = Validator.getInt(sc);
Student[] stu = new Student[num_Students];
for(int i =0 ; i<stu.length ;i++)
{
int count = 1;
String lname = Validator.getString(sc,"Student " + count + " Last Name: ");
String fname=Validator.getString(sc,"Student " + count + " First Name: ");
System.out.print("Student " + count + " Score: ");
int score= Validator.getIntWithInRange(sc,0,100);
System.out.println();
count++;
stu[i]= new Student(lname,fname,score);
}
Arrays.sort(stu);
for (Student s: stu)
System.out.println(s.getLastName()+ " , " + s.getFirstName()+ ":" + s.getScore());
}
}
Student.java文件
public class Student实现Comparable {
private String lastname;
private String firstname;
private int score;
public Student(String lastname,String firstname,int score ){
this.lastname= lastname;
this.firstname = firstname;
this.score=score;
}
public String getLastName()
{
return lastname;
}
public String getFirstName()
{
return firstname;
}
public int getScore()
{
return score;
}
public int compareTo(Object o)
{
Student s = (Student) o;
int comparison;
final int EQUAL = 0;
comparison=this.lastname.compareTo(s.lastname);
if(comparison != EQUAL)
return comparison;
else comparison = this.firstname.compareTo(s.firstname);
if(comparison!= EQUAL)
return comparison;
return EQUAL;
}
}
验证文件:
import java.util.Scanner;
public class Validator {
public static String getString(Scanner sc , String prompt)
{
/* System.out.print(prompt);
String s = sc.next();
if (s.equals(""))
return "Enter some name"; // read the user entry
else return s ;*/
String s = "";
// Scanner sc1 = new Scanner(System.in); // System.out.println(prompt);
boolean isValid = false;
while (isValid == false )
{
System.out.print(prompt);
s = sc.nextLine();
if (s.equals("")){
System.out.println("This entry is required. Try again.");
}
else
isValid = true;
}
return s;
}
public static int getInt(Scanner sc)
{
int i = 0;
boolean isValid = false;
while (isValid == false)
{
if (sc.hasNextInt())
{
i = sc.nextInt();
isValid = true;
}
else
{
System.out.println("Error! Invalid integer value. Try again.");
}
sc.nextLine();
// discard any other data entered on the line
}
return i;
}
public static int getIntWithInRange(Scanner sc,int min, int max)
{
int i = 0;
boolean isValid = false;
while (isValid == false)
{
i = getInt(sc);
if (i < min)
System.out.println("Error!Number must be greater than " + (min-1) + ".");
else if (i > max)
System.out.println("Error! Number must be less than " + (max+1) + ".");
else
isValid = true;
}
return i;
}
}
再一次。非常感谢所有人。
的问候, 凯西
答案 4 :(得分:-1)
你有静态void main函数,它有2个参数 - int argc 和 string [] argv 第一个 - 第二个参数中的行数 第二个参数 - 命令行由空格分割 因此,您需要运行for循环,将每个命令行参数存储到对象中
static void main(int argc, string [] argv)
{
Obj [] objs = new Obj[argc];
for(int i = 0; i < argc; i++)
obj[i].value = argv[i];
}