Question

所以我正在处理使用cookie身份验证的网络。如果我获得未授权的401或406，那么我知道cookie已过期（对于1 HR有效），因此我使用存储的令牌登录以获取新的cookie。一旦我这样做，我想再次尝试呼叫，所以我在块上进行递归调用。在一个未知的案例中，如果我在成功刷新cookie后继续获得401或406，它将无限递归。我只想再试一次。我该如何阻止它？

我尝试在第一次调用后将requestID设置为-1，并在if(requestID == -1)不递归的if语句中设置。但由于requestID是一个块变量，它会抛出异常＆＃34;变量不可分配（缺少__block类型说明符。

+ (void)fullRequestWithBlock:(void (^)(NSDictionary *fullRequest, NSError *error))block forID: (NSString*) requestID forUID: (NSString *) userID{

NSString *pathSuffix = [NSString stringWithFormat:@"GetRequestInfo?requestId=%@&userId=%@", requestID, userID];
[[AFAppAPIClient sharedClient] getPath:pathSuffix parameters:[NSDictionary dictionaryWithObject:@"false" forKey:@"include_entities"] success:^(AFHTTPRequestOperation *operation, id JSON) {

    id innerJSON = [JSON objectForKey:@"d"];
    //NSStringEncoding encoding;
    NSMutableDictionary *requestData = [[NSMutableDictionary alloc] initWithDictionary:innerJSON];

    [requestData removeObjectForKey:@"requestor"];
    [requestData removeObjectForKey:@"shortDesc"];
    [requestData removeObjectForKey:@"fullDesc"];

    if (block) {
        block([NSDictionary dictionaryWithDictionary:fullDescription], nil);
    }
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {

    if ([[[error localizedDescription] substringFromIndex:[[error localizedDescription] length] - 3] isEqualToString:@"406"])
    {
        NSUserDefaults *userDefaults = [NSUserDefaults standardUserDefaults];
        NSString *storedToken = [userDefaults stringForKey:@"storedToken"];

        [Login tokenLoginIDWithBlock:^(NSString *userID, NSError *error)
        {
             if (!error)
                 {
                     NSLog(@"Reaunthenciated User with ID: %@", userID);

                     [self fullRequestWithBlock:^(NSDictionary *requests, NSError *error) {
                         if (!error) {
                             if (block) {
                                 block([NSDictionary dictionaryWithDictionary:requests], nil);
                             }
                         }
                         else{
                             block([NSDictionary dictionary], error);
                         }

                     } forID:requestID forUID:userID];

                 }
                 else{
                     block([NSDictionary dictionary], error);
                 }
             } forToken:storedToken];

        }
    }
    else if (block) {
        block([NSDictionary dictionary], error);
    }
}];

}

阻止块中的递归

0 个答案: