Question

这是我试图循环的滑块：

http://sixrevisions.com/demo/slideshow/final.html

我能够添加

timer = window.setInterval("autoSlide()", 5000); 
function autoSlide(){ jQuery("#rightControl").click(); }

到jQuery编码结束并让它每5秒移动到下一张幻灯片。但是，在最后一张幻灯片之后，它只是继续“单击”rightControl按钮。如何在最后一张幻灯片后循环播放？

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
  var currentPosition = 0;
  var slideWidth = 560;
  var slides = $('.slide');
  var numberOfSlides = slides.length;

  // Remove scrollbar in JS
  $('#slidesContainer').css('overflow', 'hidden');

  // Wrap all .slides with #slideInner div
  slides
    .wrapAll('<div id="slideInner"></div>')
    // Float left to display horizontally, readjust .slides width
    .css({
      'float' : 'left',
      'width' : slideWidth
    });

  // Set #slideInner width equal to total width of all slides
  $('#slideInner').css('width', slideWidth * numberOfSlides);

  // Insert controls in the DOM
  $('#slideshow')
    .prepend('<span class="control" id="leftControl">Clicking moves left</span>')
    .append('<span class="control" id="rightControl">Clicking moves right</span>');

  // Hide left arrow control on first load
  manageControls(currentPosition);

  // Create event listeners for .controls clicks
  $('.control')
    .bind('click', function(){
    // Determine new position
    currentPosition = ($(this).attr('id')=='rightControl') ? currentPosition+1 : currentPosition-1;

// Hide / show controls
manageControls(currentPosition);
// Move slideInner using margin-left
$('#slideInner').animate({
  'marginLeft' : slideWidth*(-currentPosition)
});
  });

  // manageControls: Hides and Shows controls depending on currentPosition
  function manageControls(position){
    // Hide left arrow if position is first slide
    if(position==0){ $('#leftControl').hide() } else{ $('#leftControl').show() }
    // Hide right arrow if position is last slide
    if(position==numberOfSlides-1){ $('#rightControl').hide() } else{ $('#rightControl').show() }
  } 
});

Answer 1

我认为this jsfiddle是您正在寻找的。

基本上取而代之：

currentPosition = ($(this).attr('id')=='rightControl') ? currentPosition+1 : currentPosition-1;

使用以下内容检查幻灯片放映的一端：

if ($(this).attr('id') == 'rightControl') { currentPosition = currentPosition >= slides.length - 1 ? 0 : currentPosition + 1; } else { currentPosition = currentPosition <= 0 ? slides.length - 1 : currentPosition - 1; }

我继续前进并添加了左移的检查，但你可能不会需要它。

有人可以解释如何使这个jQuery滑块自动播放和循环？

1 个答案: