URL重定向问题

时间:2010-02-14 16:40:27

标签: python url redirect bit.ly

我有以下网址

http://bit.ly/cDdh1c

当您将上述网址放入浏览器并按Enter键时,它将重定向到以下网址 http://www.kennystopproducts.info/Top/?hop=arnishad

但是当我尝试通过python程序(下面你可以看到代码)找到相同的上面url http://bit.ly/cDdh1c之后找到基本网址(在删除所有重定向网址之后)时,我得到以下网址{ {3}}作为基本网址。请参阅下面的日志文件

为什么同一个url在浏览器和python程序中表现不同。我应该在python程序中更改哪些内容以便它可以重定向到正确的url?我想知道这种奇怪的行为是如何发生的。?

我观察到类似行为的其他网址

  1. http://www.cbtrends.com/ ====> http://bit.ly/bEKyOx (通过浏览器)
  2. http://cgi.ebay.com/ws/eBayISAPI.dll?ViewItem&item=150413977509(通过python 程序)

          maxattempts = 5
          turl = url
          while (maxattempts  >  0) :               
            host,path = urlparse.urlsplit(turl)[1:3]
            if  len(host.strip()) == 0 :
               return None
    
            try: 
                    connection = httplib.HTTPConnection(host,timeout=10)
                    connection.request("HEAD", path)
                    resp = connection.getresponse()                      
            except:                         
                     return None                     
            maxattempts = maxattempts - 1
            if (resp.status >= 300) and (resp.status <= 399):
                self.logger.debug("The present %s is a redirection one" %turl)
                turl = resp.getheader('location')
            elif (resp.status >= 200) and (resp.status <= 299) :
                self.logger.debug("The present url %s is a proper one" %turl)
                return turl
            else :
                #some problem with this url
                return None               
          return None
    
  3. 日志文件供您参考

    2010-02-14 10:29:43,260 - paypallistener.views.MrCrawler - INFO - Bringing down the base URL
    2010-02-14 10:29:43,261 - paypallistener.views.MrCrawler - DEBUG - what is the url=http://bit.ly/cDdh1c
    2010-02-14 10:29:43,994 - paypallistener.views.MrCrawler - DEBUG - The present http://bit.ly/cDdh1c is a redirection one
    2010-02-14 10:29:43,995 - paypallistener.views.MrCrawler - DEBUG - what is the url=http://www.cbtrends.com/get-product.html?productid=reFfJcmpgGt95hoiavbXUAYIMP7OfiQn0qBA8BC7%252BV8%253D&affid=arnishad&tid=arnishad&utm_source=twitterfeed&utm_medium=twitter
    2010-02-14 10:29:44,606 - paypallistener.views.MrCrawler - DEBUG - The present http://www.cbtrends.com/get-product.html?productid=reFfJcmpgGt95hoiavbXUAYIMP7OfiQn0qBA8BC7%252BV8%253D&affid=arnishad&tid=arnishad&utm_source=twitterfeed&utm_medium=twitter is a redirection one
    2010-02-14 10:29:44,607 - paypallistener.views.MrCrawler - DEBUG - what is the url=http://www.cbtrends.com/
    2010-02-14 10:29:45,547 - paypallistener.views.MrCrawler - DEBUG - The present url http://www.cbtrends.com/ is a proper one
    http://www.cbtrends.com/
    

2 个答案:

答案 0 :(得分:1)

您的问题是,当您调用urlsplit时,您的路径变量只包含路径并且缺少查询。

所以,请尝试:

import httplib
import urlparse

def getUrl(url):
    maxattempts = 10
    turl = url
    while (maxattempts  >  0) :               
        host,path,query = urlparse.urlsplit(turl)[1:4]
        if  len(host.strip()) == 0 :
            return None
        try: 
            connection = httplib.HTTPConnection(host,timeout=10)
            connection.request("GET", path+'?'+query)
            resp = connection.getresponse()
        except:                         
            return None                     
        maxattempts = maxattempts - 1
        if (resp.status >= 300) and (resp.status <= 399):
            turl = resp.getheader('location')
        elif (resp.status >= 200) and (resp.status <= 299) :
            return turl
        else :
            #some problem with this url
            return None               
    return None
print getUrl('http://bit.ly/cDdh1c')

答案 1 :(得分:1)

你的问题来自这一行:

host,path = urlparse.urlsplit(turl)[1:3]

你要省略查询字符串。因此,在您提供的示例日志中,您将执行的第二个HEAD请求将在http://www.cbtrends.com/get-product.html上没有GET参数。在浏览器中打开该网址,您会看到它重定向到http://www.cbtrends.com/

您必须使用urlsplit返回的元组的所有元素来计算路径。

parts = urlparse.urlsplit(turl)
host = parts[1]
path = "%s?%s#%s" % parts[2:5]