php yii无法使用useridentity组件登录

时间:2014-03-24 17:39:10

标签: php yii

这是我的身份验证控制器

class AuthController  extends Controller
{

    public function actionLogin()
    {
        $model = new LoginForm;

        $post = Yii::app()->request->getPost('LoginForm');
        // If form is submitted
        if($post) {
            $identity = new UserIdentity($post['username'], $post['password']);

            if($identity->authenticate()) {  // loop enters but could not get id
                echo Yii::app()->user->id;
                echo Yii::app()->user->getId();
            } else {
                echo 'failed';
            }
            //exit;
        }
        $this->render('login', array('model' => $model));   
    }
}

这是我的UserIdentity.php

class UserIdentity extends CUserIdentity
{


    private $_id;

    public function authenticate()
    {   
        $user = SchLogins::model()->findByAttributes(array('username' => $this->username));
        if(is_null($user)) {
            $this->errorCode=self::ERROR_USERNAME_INVALID;
        } else if($user->password != $this->password) {
            $this->errorCode=self::ERROR_PASSWORD_INVALID;
        } else {

            $this->_id = $user->id;

            $this->errorCode=self::ERROR_NONE;
        }

        return !$this->errorCode;
    }


    public function getId()
    {
        return $this->_id;
    }
}

在上面的代码中我遇到了获取用户ID的问题(即)Yii::app()->user->getId();这没有返回任何内容以及我做了上述代码的错误

1 个答案:

答案 0 :(得分:0)

您正在创建LoginForm实例$model但您从未使用它来实际登录。如果您使用的是标准LoginForm模型,那么它就是与UserIdentity类进行交互的内容。它应该是这样的:

if($post) {
    $model->attributes = $_POST['LoginForm'];

    if ($model->validate() && $model->login()) {  // loop enters but could not get id
        echo Yii::app()->user->id;
        echo Yii::app()->user->getId();
    } else {
        echo 'failed';
    }
    //exit;
}

如果您查看LoginForm的login()功能,您会看到它调用Yii::app()->user->login($this->_identity,$duration);,这实际上是设置了Yii::app()->user,而您的方法被跳过了。