Question

执行查询时收到以下错误消息：

PDOException: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax near '://www.website.com.br/Manual_01/Realm/1980-1988/R7678.htm' na linha 1: SELECT (field_data_field_url.entity_id) FROM field_data_field_url WHERE field_data_field_url.field_url_value = http//www.website.com.br/Manual_01/Realm/1980-1988/R7678.htm ; Array ( ) em _xmlrpc_troca()

这是我的Drupal模块的功能：

$query = db_query("SELECT (field_data_field_url.entity_id) FROM field_data_field_url WHERE field_data_field_url.field_url_value = $url ");
 foreach ($query as $record) {
 echo $record->entity_id; 
}
 return $record;

如果我将'$ url'包裹起来''，那么它可以工作：

$query = db_query("SELECT (field_data_field_url.entity_id) FROM field_data_field_url WHERE field_data_field_url.field_url_value = '$url' ");

但我在xmlrpc响应时收到错误，因为它在发送响应时发回''并且我得到错误。这个响应带有正确的数据，但它没用，因为我无法解析它。有人知道如何解决它？

编辑：

响应是这样的：

body: '30254<?xml version="1.0"?>\n\n<methodResponse>\n  <params>\n  <param>\n    <value><struct>\n  <member><name>entity_id</name><value><string>30254</string></value></member>\n</struct></value>\n  </param>\n  </params>\n</methodResponse>\n\n'

最后'30254和'是问题所在。我收到此错误消息：

ExpatError: not well-formed (invalid token): line 1, column 5

Answer 1

您应该尝试使用db_query参数。

<?php $query = db_query('SELECT (field_data_field_url.entity_id) FROM field_data_field_url WHERE field_data_field_url.field_url_value = :url', array(':url' => $url)); ?>

您也可以尝试使用db_select（）函数。

<?php 
$select = db_select('field_data_field_url', 'fdfu'); // fdfu is an alias
$select->fields('fdfu', array('entity_id'));
$select->condition('field_url_value', $url);
$query = $select->execute();

foreach($query as $result) {
   echo $record->entity_id; 
}
?>

PDOException：SQLSTATE [42000]：语法错误或访问冲突Mysql

1 个答案: