以编程方式创建路径不适用于所需
我有这个自定义控件
<Grid Name="PanelInferior" Grid.Row="5" Grid.ColumnSpan="5">
<Grid.ColumnDefinitions>
<ColumnDefinition x:Name="NombrePiezaHolder" Width="2*"/>
<ColumnDefinition x:Name="Simbol1" Width="1*"/>
<ColumnDefinition x:Name="Simbol2" Width="1*"/>
<ColumnDefinition x:Name="Simbol3" Width="1*"/>
<ColumnDefinition x:Name="Simbol4" Width="1*"/>
</Grid.ColumnDefinitions>
<Grid.RowDefinitions>
<RowDefinition Height="1*"/>
</Grid.RowDefinitions>
<TextBlock x:Name="NombrePieza" Text="{Binding ElementName=Esta_Pieza,Path=Pieza.Id}" Margin="0" Height="Auto" Width="Auto" Panel.ZIndex="0" VerticalAlignment="Center" Foreground="{DynamicResource {x:Static SystemColors.HotTrackBrushKey}}" FontWeight="ExtraBold" HorizontalAlignment="Center"/>
<Viewbox x:Name="PanelInferior1" Grid.Row="0" Grid.Column="1" Height="Auto" Width="Auto">
<Grid x:Name="PanelInferior1Contenedor" >
</Grid>
</Viewbox>
<Viewbox x:Name="PanelInferior2" Grid.Row="0" Grid.Column="2" Height="Auto" Width="Auto">
<Grid x:Name="PanelInferior2Contenedor">
<Path x:Name="EndodonciaPorRealizar" Data="M-2.1394273E-06,993.43869 L68.000003,995 32.942219,2.8478794E-06 z" Height="200" Margin="0" Stretch="Fill" Width="200" Fill="#FFBB2727"/>
</Grid>
</Viewbox>
<Viewbox x:Name="PanelInferior3" Grid.Row="0" Grid.Column="3" Height="Auto" Width="Auto">
<Grid x:Name="PanelInferior3Contenedor">
</Grid>
</Viewbox>
<Viewbox x:Name="PanelInferior4" Grid.Row="0" Grid.Column="4" Height="Auto" Width="Auto">
<Grid x:Name="PanelInferior4Contenedor">
</Grid>
</Viewbox>
</Grid>
</Grid>
</UserControl>
网格 PanelInferior 在运行时有4个地方可以绘制，如果我添加了另一个具有相同属性的路径，那么第2列就已经有了一个路径（仅用于测试）它不像其他人那样绘制（Column2）
这是传递给de TextToPath函数的字符串：
x:Name="EndodonciaPorRealizar"~Data="M-2.1394273E-06,993.43869 L68.000003,995 32.942219,2.8478794E-06"~Height="200"~Margin="0"~Stretch="Fill"~Width="200"~Fill="#FFBB2727"
这是在运行时创建路径的代码
public static Path TextToPath(String PathText, string name )
{
Path NewPath = new Path();
NewPath.Name = name;
string PropertieName = "";
string PropertieValue = "";
string[] Properties = PathText.Split('~');
foreach (string Propertie in Properties)
{
string[] PropertieParts = Propertie.Split('=');
PropertieName = PropertieParts[0];
PropertieValue = PropertieParts[1].Replace('"', " ".ToCharArray()[0]);
switch (PropertieName)
{
case "Data":
NewPath.Data = Geometry.Parse(PropertieValue);
break;
case "Height":
if (PropertieValue == " Auto ")
NewPath.Height = Double.NaN;
else
NewPath.Height = double.Parse(PropertieValue);
break;
case "Width":
if (PropertieValue == " Auto ")
NewPath.Width = Double.NaN;
else
NewPath.Width = double.Parse(PropertieValue);
break;
case "Fill":
NewPath.Fill = (SolidColorBrush)(new BrushConverter().ConvertFrom(PropertieValue));
break;
case "Margin":
string[] Margins = PropertieValue.Split(',');
switch (Margins.Count())
{
case 1:
NewPath.Margin = new Thickness(double.Parse(PropertieValue));
break;
case 4:
NewPath.Margin = new Thickness(
double.Parse(Margins[0]),
double.Parse(Margins[1]),
double.Parse(Margins[2]),
double.Parse(Margins[3])
);
break;
}
break;
case "HorizontalAlignment":
switch (PropertieValue)
{
case "Left":
NewPath.HorizontalAlignment = HorizontalAlignment.Left;
break;
case "Center":
NewPath.HorizontalAlignment = HorizontalAlignment.Center;
break;
case "Right":
NewPath.HorizontalAlignment = HorizontalAlignment.Right;
break;
case "Stretch":
NewPath.HorizontalAlignment = HorizontalAlignment.Stretch;
break;
}
break;
case "Stretch":
switch (PropertieValue)
{
case "Fill":
NewPath.Stretch = Stretch.Fill;
break;
case "None":
NewPath.Stretch = Stretch.None;
break;
case "Uniform":
NewPath.Stretch = Stretch.Uniform;
break;
case "UniformToFill":
NewPath.Stretch = Stretch.UniformToFill;
break;
}
break;
case "VerticalAlignment":
switch (PropertieValue)
{
case "Bottom":
NewPath.VerticalAlignment = VerticalAlignment.Bottom;
break;
case "Center":
NewPath.VerticalAlignment = VerticalAlignment.Center;
break;
case "Stretch":
NewPath.VerticalAlignment = VerticalAlignment.Stretch;
break;
case "Top":
NewPath.VerticalAlignment = VerticalAlignment.Top;
break;
}
break;
}
}
return NewPath;
}
最后这段代码添加了网格的新路径（在这种情况下为Simbolo.Path = null和posicion = PosicionSimbolo.Abajo
public void DrawSimbol(ISimbolo simbolo)
{
if (!simbolo.Dibujado)
{
//Si no se especifica la propiedad path del simbolo, se procede a colorear la superficie
if (simbolo.Path == null)
{
if (simbolo.FillColor != null)
{
Shape ThisShape = IdSuperficieToShape(simbolo.Superficie.Id);
if (ThisShape != null)
ThisShape.Fill = (SolidColorBrush)(new BrushConverter().ConvertFrom(simbolo.FillColor));
}
}
else
{
try
{
PosicionSimbolo posicion = SimbolTools.posicion(simbolo.DibujarEn);
ContadorSimbolos += 1;
switch (posicion)
{
case PosicionSimbolo.Abajo:
PosicionPanelInferior +=1;
string Nombre = string.Format("PanelInferior{0}", PosicionPanelInferior.ToString().Trim());
Path MyPath = SimbolTools.TextToPath(simbolo.Path, Nombre);
switch (PosicionPanelInferior)
{
case 1:
PanelInferior1Contenedor.Children.Add(MyPath);
break;
case 2:
PanelInferior2Contenedor.Children.Add(MyPath);
break;
case 3:
PanelInferior3Contenedor.Children.Add(MyPath);
break;
case 4:
PanelInferior4Contenedor.Children.Add(MyPath);
break;
}
MyPath.Visibility = System.Windows.Visibility.Visible;
break;
}
}
catch (Exception e)
{
throw new ParadigmaNException(Errores.GRAMAS_NoSePudoDibujarSimbolo,e);
}
}
}
}
我希望这两条路径具有相同的形状，但结果如下：
之后我有一些问题： 1-为什么形状不一样？ 2-有一种方法可以检索代码添加的路径的XAML代码吗？这是因为我想与column2的路径的静态XAML进行比较 3-以编程方式编写与de column2路径匹配的路径的正确方法是什么？
相关问题
最新问题
- 我写了这段代码，但我无法理解我的错误
- 我无法从一个代码实例的列表中删除 None 值，但我可以在另一个实例中。为什么它适用于一个细分市场而不适用于另一个细分市场？
- 是否有可能使 loadstring 不可能等于打印？卢阿
- java中的random.expovariate()
- Appscript 通过会议在 Google 日历中发送电子邮件和创建活动
- 为什么我的 Onclick 箭头功能在 React 中不起作用？
- 在此代码中是否有使用“this”的替代方法？
- 在 SQL Server 和 PostgreSQL 上查询，我如何从第一个表获得第二个表的可视化
- 每千个数字得到
- 更新了城市边界 KML 文件的来源？