我正在使用Visual C#2010,我喜欢将DLL C ++中的图像发送到我的Visual C#2010。图像有166 * 166 * 24将图像从DLL C ++发送到C#。我使用此代码:
的main.cpp
unsigned char* test()
{
read image from filename
Mat OriginalImg = imread(fileName, CV_LOAD_IMAGE_COLOR);
return (OriginalImg.data);}
OriginalImg.data return the pointer to the image.
main.h
extern "C" { __declspec(dllexport) unsigned char* test();}
在我的程序Visual C#中,我使用了这段代码:
[DllImport("testng.dll", CallingConvention = CallingConvention.Cdecl)]
private static extern IntPtr test();
IntPtr intPtr1;
BitmapImage bitmapImage;
calling the c++ dll
intPtr1 = test(1);
if (intPtr1.ToString().CompareTo("0") != 0)
{
create a bitmap with the pointer
Bitmap bitmap = new Bitmap(166, 166, 3 * 166, System.Drawing.Imaging.PixelFormat.Format24bppRgb, intPtr1);
to show the bitmap i need to convert it to a bitmap image
bitmapImage=convertBitmapToBitmapImage(bitmap);
System.Windows.Media.ImageBrush ib = new System.Windows.Media.ImageBrush();
ib.ImageSource = bitmapImage;
i put the image received from c++ dll like a background to my canvas: canvasImage
windows.canvasImage.Background = ib;
}
BitmapImage convertBitmapToBitmapImage(Bitmap bitmap)
{
IntPtr hBitmap = bitmap.GetHbitmap();
BitmapSource retval;
try
{
retval = Imaging.CreateBitmapSourceFromHBitmap(
hBitmap,
IntPtr.Zero,
Int32Rect.Empty,
BitmapSizeOptions.FromEmptyOptions());
}
finally
{
//DeleteObject(hBitmap);
}
return (BitmapImage)retval;
}
答案 0 :(得分:0)
我的猜测是cv::Mat
数据的指针在函数test()
返回后不再有效,因为变量OriginalImg
超出范围,析构函数已清除OriginalImg
数据。如果可以防止自动销毁变量,请尝试将OriginalImg
设为全局。
通常,我建议为OpenCV制作通用的C ++ / CLI包装器。关于此问题的a post。例如,我现在正在处理与您相同的问题,并且我在C ++ / CLI中创建了一个System.Drawing.Bitmap
对象而没有任何DllImport
...