Question

我收到警告，mysql_fetch_array()期望参数1为资源。这是我获取帖子数量然后打印行数的代码。

<?php
    $result = mysql_query("SELECT * FROM amityusers WHERE added_by='$user'");            

    while($array = mysql_fetch_array($result))
    {
        $hoot = $array['post'];
        $num_hoot = mysql_num_rows($hoot);
    }
?>

如何打印行数以及问题是什么？

Answer 1

只需取出循环外的mysql_num_rows()，然后将变量更改为$result

$num_hoot = mysql_num_rows($result);

Answer 2

试试这个适合你的

$result = mysql_query("SELECT * FROM amityusers WHERE added_by='$user'") or die(mysql_error());   
    $num_row = mysql_num_rows($result); 

    $post = array();

    if($num_row > 1)
    {        
    while($array = mysql_fetch_array($result))
    {
    $post[]= $array['post'];   
    }
    var_dump($post);
    }
    else
    {
    echo 'no row found';
    }

Answer 3

让我们将您的MySQL转换为MySQLi。把你的mysqli_num_rows放在循环之外。 AND 将mysqli_num_rows()中的变量替换为 $ result 而不是 $ hoot 。不要忘记 echo ：

<?php

$yourConnection=mysqli_connect("host","username","password","yourDatabase");

if(mysqli_connect_errno()){
echo "Error".mysqli_connect_error();
}

$result = mysqli_query($yourConnection,"SELECT * FROM amityusers WHERE added_by='$user'");
while($array = mysqli_fetch_array($result)){
$hoot = $array['post'];
}
$num_hoot = mysqli_num_rows($result); /* PUT THIS OUTSIDE YOUR LOOP AND PUT $result INSTEAD OF $hoot VARIABLE*/

echo "Total result of ".$num_hoot;

?>

Answer 4

试试这个，您可以使用count()获取帖子

while($array = mysqli_fetch_array($result)){
    $hoot = $array['post'];
   echo $num_hoot = count($hoot); 
 }

Answer 5

在$result

中使用mysql_num_rows

$num_hoot = mysql_num_rows($result);

Answer 6

首先，不要使用已弃用的mysql函数

$result = mysql_query("SELECT * FROM amityusers WHERE added_by='$user'") or die(mysql_error());   
$num_hoot = mysql_num_rows($result);         
while($array = mysql_fetch_array($result))
{
$post= $array['post'];   
}

Answer 7

尝试这种方式

$con = mysql_connect("localhost", "root", "");  
$selectdb = mysql_select_db("mydbname",$con);  
$result = mysql_query("select * from student");  
$number_of_rows = mysql_num_rows($result);  
echo "Number of rows fetched are : ". $number_of_rows;

mysql_num_rows在输出行数时给出错误？

7 个答案: