警告不兼容的指针类型

Question

我为散列函数编写了这个块：

#include "debug.h"
#include "hash.h"

unsigned hash_add(unsigned char *name)
{
unsigned h;
for(h=0;*name;h+=name++);
return h;
}

我一直得到：

hashadd.c:7:17: warning: assignment makes integer from pointer without a cast [enabled  by default]

Answer 1

for``h+=name++的最后一个表达式是将地址（name的类型为unsigned char *）分配给h（类型unsigned int）。将其更改为

 for(h = 0; *name; h += *name++);  
                        ^Dereference the pointer before assigning to h.

Answer 2

为什么不通过保持哈希初始化，迭代和累积分开来以自然的方式编写代码？

unsigned hash_add(const unsigned char *name) {
    unsigned h = 0;
    for(; *name; name++) h += *name;
    return h;
}