我是一名初学IT11学生,我们应该制作一个程序,该程序将读取一个人出生的日期,月份和年份的数量。
例如,1982年9月3日出生的人将输入数字
3,9和1982
分为三个单独的JOP.showInputDialogs
。
如果输入的值不正确,程序应该给出一个非常具体的错误消息,说明它无效的原因,并要求用户再次输入信息。在进行无效输入时,用户永远不必重新输入多个值(例如,如果日期无效,则用户只需重新输入日期,而不是月份或年份。)
该程序将以下列格式告诉该人他们的出生日期:
你出生于1982年9月3日。
日期格式必须如上所示。
重要 - 程序必须对无效月份进行错误检查(有效期在1到12之间) - 程序必须对无效年份进行错误检查(有效> = 1800) - 程序必须对月份无效的日期进行错误检查(有效期为1到月之间(30,31,28或29)) - 程序必须仅在LEAP年份允许2月29日。
我坚持使用的部分包含无效日期的错误消息。例如,如果我在4月31日输入,该程序应该返回一条错误消息,说明" 4月只有30天"等等。我该怎么做?这是我到目前为止所得到的。
import javax.swing.*;
public class A6DateProgram {
public static void main(String[] args) {
int year = getYearFromUser(); //gets user input for year
int month = getMonthFromUser(); //gets user input for month
int day = getDateFromUser(month, year); //gets user input for date
//tells the user their birthdate
System.out.println("You were born " + Months(month) + " " + day + ", "+ year + " " + ".");
} //main
//asks user for year
public static int getYearFromUser(){
String year; //asks user for year
int year1 = 0;
String errorMessage = "";
boolean isLeap = false;
do{
year = JOptionPane.showInputDialog(errorMessage + "Please enter the year you were born in. (>1800)");
if (year == null) {
System.out.println("You clicked cancel");
System.exit(0);
}
// parse string to an int
try {
year1 = Integer.parseInt(year); //parses recieved number to an int
} catch (Exception e) {
errorMessage = "Invalid integer\n"; //if user does not input valid integer
continue; //continues to condition [while(true);]
} // catch
isLeap = validateYear(year1);
if(year1 < 1800 || year1 > 2400){ //number limitation
errorMessage = "Your number must be greater than 1800 or less than 2400. \n"; //if user does not input a valid integer between limit
continue; //continues to condition [while(true);]
}
break;
} while(true);
return year1;
} //getYearFromUser
public static boolean validateYear(int year){
return (year % 400 == 0 ) ? true : (year%100 == 0)? false : (year % 4 == 0)? true: false;
}
//asks user for month
public static int getMonthFromUser(){
String month;
int num = 0;
String errorMessage = "";
do{
month = JOptionPane.showInputDialog(errorMessage + "Please enter the month you were born in as a valid integer. (ex. January = 1)");
if (month == null) {
System.out.println("You clicked cancel");
System.exit(0);
}
// parse string to an int
try {
num = Integer.parseInt(month);
} catch (Exception e) {
errorMessage = "Invalid integer\n";
continue; //continues to condition [while(true);]
} // catch
if(num > 12 || num < 1){
errorMessage = "A year only has 12 months. \n";
continue; //continues to condition [while(true);]
}
break;
} while(true);
return num;
} //getMonthFromUser
//asks user for date
public static int getDateFromUser(int month, int year){
String date;
int day = 0;
String errorMessage = "";
boolean ToF = false;
do{
date = JOptionPane.showInputDialog(errorMessage + "Please enter the date you were born in. (1-31)");
//user clicks cancel
if (date == null) {
System.out.println("You clicked cancel");
System.exit(0);
}
// parse string to an int
try {
day = Integer.parseInt(date);
} catch (Exception e) {
errorMessage = "Invalid integer\n";
continue; //continues to condition [while(true);]
} // catch
ToF = validate(year, month, day); //giving boolean ToF a method to validate the day
if(ToF == false){
errorMessage = "The month you input does not have that date. \n";
continue; //continues to condition [while(true);]
}
break;
} while(true); //do
return day;
} //getDateFromUser
public static boolean validate(int year, int month, int day){
switch(month){
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
if(day < 1 || day > 31)
return false;
break;
case 2:
if(year%4 == 0 || (year%400 == 0 && year%100 != 0)){
if (day < 1 || day > 29)
return false;
}else{
if (day < 1 || day > 28)
return false;
}
break;
case 4:
case 6:
case 9:
case 11:
if(day < 1 || day > 30)
return false;
break;
}
return true;
} //validate
//resonse to user input for month
public static String Months(int month) {
switch (month) {
case 1: return "January";
case 2: return "Febrary";
case 3: return "March";
case 4: return "April";
case 5: return "May";
case 6: return "June";
case 7: return "July";
case 8: return "August";
case 9: return "September";
case 10: return "October";
case 11: return "November";
case 12: return "December";
default: return "Invalid";
} // switch
} //Months
} //A6DateProgram Class
答案 0 :(得分:1)
尝试使用SimpleDateFormat()
String date = "3";
String month = "9";
String year = "1980";
SimpleDateFormat sdf1 = new SimpleDateFormat("ddMMyyyy");
SimpleDateFormat sdf2 = new SimpleDateFormat("MMMM dd, yyyy");
Date date1 = sdf1.parse((Integer.parseInt(date)<10?"0"+date:date)+(Integer.parseInt(month)<10?"0"+month:month)+year);
String ansStr = sdf2.format(date1);
System.out.println("You were born "+ansStr);
如果您输入一个生效日期,它会自动进入下一个日期。
如果输入为29-02-2014
,则为Exmple,将为01-03-2014