Question

我试图获取网址＆＃34; / videoGame＆＃34;运行＆＃34; listAllVideoGames＆＃34;方法和＆＃34; / videoGame /＃＆＃34; （其中＃是一个数字）运行＆＃34; getVideoGame＆＃34;方法。用＆＃34; @ priority＆＃34;改变优先级注释我可以让两个URL都调用一个或另一个，但是找不到我所描述的方法。

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource{

    protected function getDao(){
        return new VideoGameDao();
    }

    /**
     * @uri /videoGame
     * @json
     * @provides application/json
     * @method GET
     */
    public function listAllVideoGames(){
        return new Response(Response::OK,$this->dao->getAllVideoGames());
    }

    /**
     * @uri /videoGame/:id
     * @json
     * @provides application/json
     * @method GET
     */
    public function getVideoGame($id){
        $vg = $this->dao->getVideoGame($id);
        if ($vg){
            return new Response(Response::OK,$vg);
        }else{
            throw new NotFoundException();
        }
    }
}

Answer 1

我发现这样做的唯一方法是为这样的GET调用创建一种调度程序：

/**
 * @uri /videoGame
 * @uri /videoGame/:id
 */
class VideoGame extends Resource{

    protected function getDao(){
        return new VideoGameDao();
    }

    /**
     * @uri /videoGame/:id
     * @provides application/json
     * @method GET
     */
    public function getVideoGames($id = 0){
        if (is_numeric($id) && $id > 0){
            return $this->getVideoGame($id);
        }else{
            return $this->getAllVideoGames();
        }
    }

    private function getVideoGame($id){
        $vg = $this->dao->getVideoGame($id);
        if ($vg){
            return new Response(Response::OK,$vg);
        }else{
            throw new NotFoundException();
        }
    }

    public function getAllVideoGames(){
        return new Response(Response::OK,$this->dao->getAllVideoGames());
    }

Tonic.PHP上有“/ resource”和“/ resource / id”URL

1 个答案: