Question

我是一个蟒蛇新手，我似乎遇到了问题，我看不出我做错了什么。我试图让它成为当我输入一个字符串时它将字符串变成猪拉丁语。问题在于，当我这样做时，它只打印出转换后的字符串中的第一个单词。有人能指出我正确的方向吗？

干杯

def pig_latin(data):
    words = data.split()
    piglatin = []
    vowels = ["a", "i", "e", "u", "o", "1", "2", "3", "4", "5", "6", 
     "7", "8", "9", "0"]

    for word in words:
        if word[0] in vowels:
            word = word + "way"
        else:
            word = word.replace(word[0],"") + word[0] + "ay"
            word = word.lower()
        piglatin.append(word)

        piglatin = "".join(piglatin)
        return piglatin

Answer 1

由于缩进不良，您的return语句位于for循环内，所以很明显它会在一次迭代后返回。
以下是修复此问题的代码以及其他一些更改：

def pigetize(text, wovels):
    return ((text + "way") if text[0] in wovels else (text[1:]+text[0]+"ay")).lower()

def pig_latin(data):
    words = data.split()
    piglatin = []
    vowels = ["a", "i", "e", "u", "o"] + [str(x) for x in range(10)]

    for word in words:
        piglatin.append(pigetize(word, wovels))

    return "".join(piglatin)

Answer 2

检查缩进。你的return语句在for循环中，所以它会在第一次迭代后返回。您希望确保return与for语句处于同一缩进级别。

def pig_latin(data): 
    words = data.split() 
    piglatin = [] 
    vowels = ["a", "i", "e", "u", "o", "1", "2", "3", "4", "5", "6", "7", "8", "9", "0"]

    for word in words:
        if word[0] in vowels:
            word = word + "way"
        else:
            word = word.replace(word[0],"") + word[0] + "ay"
            word = word.lower()
        piglatin.append(word)

    piglatin = " ".join(piglatin)
    return piglatin

for循环不迭代？

2 个答案: