Question

    <?php
// i have multiple id and user_name in my SESSION, i don't want to create a new session if 5 exist.
    if($_SESSION['paneluser'][]['user_id'] != $user_id) {
        $_SESSION['paneluser'][] = array('user_id' => $user_id, 'user_name' => $user_name);
        }
    }
    ?>

例如： id：1 身份2 id：3

user_id = 3的值，我不需要创建新的SESSION。

我想检查我的$ _SESSION中是否存在id。如果是这种情况，我不想创建新会话。我做错了什么？谢谢。

Answer 1

不是最迷人的解决方案，但您可以foreach寻找它：

$found = false;
foreach($_SESSION['paneluser'] as $user) {
    if($user['user_id'] == $user_id) { // look for the user ID in session array
        $found = true; // set your flag if its found
        break; // found what you want, no need to continue the loop
    }
}

if(!$found) { // if you didn't find it
    // create new entry
    $_SESSION['paneluser'][] = array('user_id' => $user_id, 'user_name' => $user_name);
}

Answer 2

使用array[] = 'hello';是为了向数组中添加一个元素，为了读取它你不能使用[]但该元素的当前索引。

   <?php
    // i have multiple id and user_name in my SESSION, i don't want to create a new session if 5 exist.
    if($_SESSION['paneluser']['user_id'] != $user_id) {
        $_SESSION['paneluser'] = array('user_id' => $user_id, 'user_name' => $user_name);
    }
    ?>

查找SESSION数组中是否存在密钥

2 个答案: