Question

$connect = mysql_connect("localhost", "username", "password");
if($connect) {
            mysql_selectdb('phplogin');
            $query = mysql_query("SELECT * FROM forum ORDER BY time desc");
            $query2 = mysql_query("SELECT * FROM forum");
            $data2 = mysql_fetch_array($query2);
            $id = $data2['id'];


            while($data = mysql_fetch_array($query)) {
                echo "<div class='post'>" . "<div class='leftside'>" . "<h3 class='by'>" . $data['user'] . "</h3>" . "<h5 class='date'>" . $data['time'] . "</h5>" . "</div>" . "<div class='after'>" . "</div>" . "<div class='rightside'>" . "<h2 class='title'>" . "<a href='Forum.php?$id'>" . htmlspecialchars($data['title']) . "</a>" . "</h2>" . "<p class='description'>" . htmlspecialchars($data['description']) . "</p>"  . "</div>" . "<div class='clear'>" . "</div>" . "</div>";
            }

这是我尝试过但它将所有链接的第一行ID分配给我并且我不知道该怎么做，我是php和mysql的新手，感谢您的帮助。

Answer 1

问题是您要将$id中的ID保存为变量。这只能容纳一个值。

你为什么这样做？您的查询都是从forum中选择的，您是否可以使用$data['id']？

while($data = mysql_fetch_array($query)) {
    echo "<div class='post'>" . "<div class='leftside'>" . "<h3 class='by'>" . $data['user'] . "</h3>" . "<h5 class='date'>" . $data['time'] . "</h5>" . "</div>" . "<div class='after'>" . "</div>" . "<div class='rightside'>" . "<h2 class='title'>" . "<a href='Forum.php?".$data['id']."'>" . htmlspecialchars($data['title']) . "</a>" . "</h2>" . "<p class='description'>" . htmlspecialchars($data['description']) . "</p>"  . "</div>" . "<div class='clear'>" . "</div>" . "</div>";
}

请注意，mysql_*函数为officially deprecated，因此不应在新代码中使用。您可以使用PDO或MySQLi。有关详细信息，请参阅this answer on SO。

使用MySQLi和printf()执行此操作可能如下所示。

$link = mysqli_connect("localhost", "username", "password", "dbname");
/* check connection */
if (mysqli_connect_errno()) {
        printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
}

$query = mysql_query("SELECT * FROM forum ORDER BY time desc");

if ($result = mysqli_query($link, $query)) {
        /* fetch associative array */
        while ($data = mysqli_fetch_assoc($result)) {
                printf ("<div class='post'><div class='leftside'>
                    <h3 class='by'>%s</h3>
                    <h5 class='date'>%s</h5></div><div class='after'></div><div class='rightside'>
                    <h2 class='title'><a href='Forum.php?%u'>%s</a></h2>
                    <p class='description'>%s</p></div><div class='clear'></div></div>",
                    $data['user'],
                    $data['time'],
                    $data['id'],
                    htmlspecialchars($data['title']),
                    htmlspecialchars($data['description']));
        }

        /* free result set */
        mysqli_free_result($result);
}

如何检索每行的ID，然后将其分配给链接

1 个答案: