Question

尝试使用python脚本中的选项调用shell脚本。 ./ dropbox_uploader.sh -s download / test / pictures pictures / 这一行通过SSH运行正常但从python脚本调用时出错：

import subprocess
subprocess.call(['./dropbox_uploader.sh -s download /test/pictures pictures/'])

以下是错误消息：

Traceback (most recent call last):
  File "sync.py", line 2, in <module>
    subprocess.call(['./dropbox_uploader.sh -s download /test/pictures pictures/'])
  File "/usr/lib/python2.7/subprocess.py", line 493, in call
    return Popen(*popenargs, **kwargs).wait()
  File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
    errread, errwrite)
  File "/usr/lib/python2.7/subprocess.py", line 1259, in _execute_child
    raise child_exception
OSError: [Errno 2] No such file or directory

Answer 1

如果subprocess.call的第一个参数是一个列表，它必须包含可执行文件和参数作为单独的项：

subprocess.call(['./dropbox_uploader.sh', '-s', 
                 'download', '/test/pictures', 'pictures/'])

或者，也许更方便：

import shlex
cmd = './dropbox_uploader.sh -s download /test/pictures pictures/'
subprocess.call(shlex.split(cmd))

还有一个选项可以将解析和执行委托给shell：

cmd = './dropbox_uploader.sh -s download /test/pictures pictures/'
subprocess.call(cmd, shell=True)

（但请注意security warning）

从python调用shell脚本

1 个答案: