迭代嵌套列表

Question

我有一个列表，其中包含从我的视图返回的嵌套列表，例如 -

[[1, [1, 2, 3]], [2, [2, 3, 4]], [3, [3,4,5]]]

我想要这样的东西，它可以在python中运行 -

for obj in my_list:
    for nested_obj in obj[1]:
        print nested_obj

但是使用django模板系统，如果我尝试 -

{% for obj in data_list %}
    <h2>{{obj.0}}</h2>
    <p>
    {{for nested_obj in obj.1}}
        <h5>{{nested_obj}}</h5>
    {{ endfor }}
    </p>
{% endfor %}

我明白了 -

Could not parse the remainder: ' nested_obj in obj.1' from 'for nested_obj in obj.1'

这是为什么？ 谢谢！

编辑 - 所以，这是愚蠢的 - 我写了{{for .... }}而不是{% for ... %} 谢谢@allcaps

Answer 1

{{ for x in ... }}导致TemplateSyntaxError，应为{% for x in ... %}。

python manage.py shell

from django.template import Template, Context

data_list = [[1, [1, 2, 3]], [2, [2, 3, 4]], [3, [3, 4, 5]]]
template = """
    {% for obj in data_list %}
        Obj {{obj.0}}
        {% for nested_obj in obj.1 %}
            Nested {{nested_obj}}
        {% endfor %}
    {% endfor %}
    """

t = Template(template)
c = Context({"data_list": data_list})

print t.render(c)

出：

    Obj 1

        Nested 1

        Nested 2

        Nested 3


    Obj 2

        Nested 2

        Nested 3

        Nested 4


    Obj 3

        Nested 3

        Nested 4

        Nested 5

Answer 2

也许这有效......

data_list = [[1, [1, 2, 3]], [2, [2, 3, 4]], [3, [3,4,5]]]

{% for header, remainder in data_list %}
    <h2>a</h2>
    <p>
    {{ for x in remainder }}
        <h5>{{ x }}</h5>
    {{ endfor }}
    </p>
{% endfor %}