我正在尝试制作游戏而且我真的被卡住了。问题是我无法弄清楚如何正确使用面向对象的编程。该程序应启动游戏板功能 每当数字不等于arv时。它应该用一个" O"返回新的电路板。 以下。
from random import randint
import time
class Game():
def __init__(self):
pass
def beginning(self):
print("How are you, and why are you playing my game?")
bla = str(input())
time.sleep(2)
print("Hello," + bla + ", I am glad to see you!")
time.sleep(2)
print("Anyways, the you have to guess a number from 1-20")
def gameboard(self):
self.__board = ["O","O","O","O","O"]
print(self.__board)
self.__board.pop()
return self.__board
def game(self):
number = randint(1,20)
print(number)
x = 1
arv = input()
self.arv__ = arv
while 5 > x:
if arv == number:
print("Lucky")
break
elif arv != number:
print ("haha, try again")
print("one life gone")
return gameboard()
print(self.board())
x += 1
def Main():
math = Game()
math.beginning()
math.game()
Main()
答案 0 :(得分:0)
当您只需要一个对象实例时,使用面向对象的编程往往会使程序过于复杂。我建议只有一个主要功能。
尽管如此,我修复了你的程序。尝试自己找到这些变化,因为我太懒了解释它们,抱歉。
from random import randint
import time
class Game():
def __init__(self):
pass
def beginning(self):
print("How are you, and why are you playing my game?")
bla = str(input())
time.sleep(2)
print("Hello," + bla + ", I am glad to see you!")
time.sleep(2)
print("Anyways, the you have to guess a number from 1-20")
self.__board = ["O","O","O","O","O"]
def gameboard(self):
print(self.__board)
self.__board.pop()
return self.__board
def game(self):
number = randint(1,20)
print(number)
x = 1
while 5 > x:
arv = input()
self.arv__ = arv
if arv == number:
print("Lucky")
break
elif arv != number:
print ("haha, try again")
print("one life gone")
self.gameboard()
print(self.__board)
x += 1
def Main():
math = Game()
math.beginning()
math.game()
Main()
这是您的程序版本,它避免使用OO并且更加简化:
from random import randint
lives = 5
print("Guess a number from 1 to 20")
number = randint(1, 20)
while (lives > 1 and number != int(input())):
print("incorrect")
print("lives: " + "O" * lives)
lives -= 1
if lives == 0:
print("The number was actually " + str(number))
else:
print("You were right")