如何定义新的循环函数

Question

我有这样的方法。

def run
  loop do
    sleep 0.1
    # do something
  end
end

我想这样写。

def run
  every 100, :msec do
    # do something
  end
end

如何编写像every这样的方法？

Answer 1

def every(quantity, units = :sec)
  # this could be improved but you get the idea
  quantity = quantity / 1000.0 if units == :msec
  loop do 
    sleep quantity
    yield
  end
end

every 100, :msec do
  puts Time.now
end