Java 8中的部分函数应用程序

时间:2014-03-22 11:56:13

标签: java functional-programming java-8

我想使用Java 8新引入的函数对象将一些参数部分应用于遗留方法。

以下是有问题的方法:

/**
 * Appends a {@code character} a couple of {@code times} to a {@code string}.
 * 
 * @return the string with the appended characters as a StringBuilder
 */
private static StringBuilder appendChar(char character, int times, String string) {
    StringBuilder strBuilder = new StringBuilder(string);
    for (int i = 0; i < times; i++) {
        strBuilder.append(character);
    }
    return strBuilder;
}

1 个答案:

答案 0 :(得分:15)

这实现了我想要做的事情:

/*
 * Apply two arguments. The created function accepts a String and
 * returns a StringBuilder
 */
Function<String, StringBuilder> addEllipsis = appendToMe -> appendChar(
        '.', 3, appendToMe);
/*
 * Apply one argument. This creates a function that takes another two
 * arguments and returns a StringBuilder
 */
BiFunction<String, Integer, StringBuilder> addBangs = (appendToMe,
        times) -> appendChar('!', times, appendToMe);

// Create a function by applying one argument to another function
Function<String, StringBuilder> addOneBang = appendToMe -> addBangs
        .apply(appendToMe, 1);

StringBuilder res1 = addBangs.apply("Java has gone functional", 2);
StringBuilder res2 = addOneBang.apply("Lambdas are sweet");
StringBuilder res3 = addEllipsis.apply("To be continued");

有关函数对象的所有Java预定义变体的列表,请查看here

修改

如果你有一个包含大量参数的方法,你可以编写自己的函数:

/**
 * Represents a function that accepts three arguments and produces a result.
 * This is the three-arity specialization of {@link Function}.
 *
 * @param <T>
 *            the type of the first argument to the function
 * @param <U>
 *            the type of the second argument to the function
 * @param <V>
 *            the type of the third argument to the function
 * @param <R>
 *            the type of the result of the function
 *
 * @see Function
 */
@FunctionalInterface
public interface TriFunction<T, U, V, R> {

    R apply(T t, U u, V v);
}

接受许多参数的方法;你想提供一些:

private static boolean manyArgs(String str, int i, double d, float f) {
    return true;
}

以下是使用自定义函数对象的方法:

/*
* Pass one of the arguments. This creates a function accepting three
* arguments.
*/
TriFunction<Integer, Double, Float, Boolean> partiallyApplied = (i, d, f) -> 
                                                           manyArgs("", i, d, f);

/*
* Provide the rest of the arguments
*/
boolean res4 = partiallyApplied.apply(2, 3.0, 4.0F);
System.out.println("No time for ceremonies: " + res4);