Question

这是我想要制作的tic tak脚趾游戏的源代码，我想要发生的是玩家按下Jbutton然后禁用该按钮。我知道命令是setEnbale（false）以便它锁定，但它对我不起作用。我有9个按钮，分配了动作监听器。该程序能够通过动作监听器区分玩家1和2。但是，当我试图锁定细胞时，“错误：无法找到一些符号。”出现。究竟我做错了什么？

import javax.swing.*;
import java.awt.*;
import java.awt.event.*;

public class TicTacToe extends JFrame
{
private final int HEIGHT = 450;
private final int WIDTH = 500;
private static JButton [] button = new JButton[9];
private static Action [] playerTurn = new Action[9];
private static JLabel [] label;
private int player = 1;
private static int lockButtons = 0;

public TicTacToe ()
{
    setTitle( " Tic Tac Toe ");
    setSize( HEIGHT, WIDTH);
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);

    setLayout(new GridLayout(4,3));

    int num = 0;
    for(int i = 0; i < 9; i++ )
    {

        button[i] = new JButton( "B" + i + 1);
        playerTurn[i] = new Action();
        add(button[i]);
        button[i].addActionListener(playerTurn[i]);
    }


    setVisible(true);
}


private class Action implements ActionListener
{
    public void actionPerformed(ActionEvent playerMove)
    {
        //Get button pressed using GetSource Command
        JButton whatPlayer=(JButton)(playerMove.getSource());

            if(player == 1)
            {
                player++;
                whatPlayer.setText("player1");
                whatPlayer.setEnable(false); // this is what is cause me the error
                return;
            }   

            JOptionPane.showMessageDialog(null,"Thank You For Your Input");

            if (player == 2)
            {
                player--;
                whatPlayer.setText("player2");
                return;
            }



    }
}

public static void main(String[] arg)
{
    new TicTacToe();
}   
}

Answer 1

使用，

whatPlayer.setEnabled(b)不是whatPlayer.setEnable(b)

似乎无法让我的Jbutton锁定。错误：找不到符号

1 个答案: