动态的menustrip

Question

我正在尝试使用C＃WinForm项目创建动态菜单。我的数据库结构如下所述。我可以创建顶级菜单，即“FILE”，“EDIT”，“SEARCH”。但我不能运行子菜单的递归功能。

mysql> select * from dynamicmenu;
+------+-----------------+--------+-------+-----------+
| SLN  | Child           | Parent | Level | Reference |
+------+-----------------+--------+-------+-----------+
|    1 | FILE            | NULL   |     0 | NULL      |
|    2 | EDIT            | NULL   |     0 | NULL      |
|    3 | SEARCH          | NULL   |     0 | NULL      |
|    4 | Session Manager | FILE   |     1 | 1         |
|    5 | Connect To      | FILE   |     1 | 1         |
|    6 | DO              | FILE   |     2 | 5         |
|    7 | Copy            | EDIT   |     1 | 2         |
|    8 | Paste           | EDIT   |     1 | 2         |
|    9 | Find Text       | SEARCH |     1 | 3         |
|   10 | Cut             | EDIT   |     2 | 7         |
|   11 | VMS             | FILE   |     3 | 6         |
+------+-----------------+--------+-------+-----------+
11 rows in set (0.00 sec)

c＃代码如下。

mysqlConn conn;
private void Form1_Load(object sender, EventArgs e)
{
    conn = new mysqlConn();
    conn.OpenConnection();
    MySqlCommand cmd = new MySqlCommand("Select * from dynamicmenu", conn.connection);
    MySqlDataReader dr = cmd.ExecuteReader();
    while (dr.Read())
    {
        if (dr["Parent"].ToString() == "")
        {
            menuStrip1.Items.Add(dr["Child"].ToString());
        }

        else if (dr["Parent"].ToString() != "")
        {

            AddSubMenu(new ToolStripMenuItem(dr["Child"].ToString()), dr["Parent"].ToString());
        }
    }
    dr.Close();
    conn.CloseConnection();

}

private void AddSubMenu(ToolStripMenuItem ChildItem, string ParentItem)
{
    foreach (ToolStripMenuItem item in menuStrip1.Items)
    {
        if (ParentItem == item.Name)
        {
            item.DropDownItems.Add(ChildItem);
        }
    }
}

请告知。

Answer 1

使用toString()代替name。

private void AddSubMenu(ToolStripMenuItem ChildItem, string ParentItem)
{
    foreach (ToolStripMenuItem item in menuStrip1.Items)
    {
        if (ParentItem == item.ToString())
        {
            item.DropDownItems.Add(ChildItem);
        }
    }
}