SyntaxError {stack：（...），message：＆＃34; Unexpected token＆lt;＆＃34;}

Question

我正在使用jquery ajax调用

var data="name"+get_name;
        $.ajax({
            type:"GET",
            url:"php/getAllInfo.php",
            data:data,
            dataType:"json",
            success: function(data){
                var allDetails=data;
                console.log(allDetails);
            },
            error:function(jqXHR, textStatus, errorThrown){
             console.log(errorThrown);
            },
             complete: function(){

            }
        });

PHP

$name = trim($_GET['name']);

$mysql_resultset = mysqli_query($con, "SELECT dod.deviceId, drs.cpuUtilization FROM device_owner_details dod, device_realtime_stats drs WHERE  dod.name = '$name' AND drs.deviceId= dod.deviceId ");

$rows_data = mysqli_fetch_assoc($mysql_resultset);

$all_details = array('deviceId'=> $rows_data['deviceId'], 'cpuUtilization' => $rows_data['cpuUtilization']);

$response = json_encode($all_details);
echo $response;

mysqli语句是正确的。但是它给出了语法错误，编码中的错误是什么。这里cpuUtilization值为NULL

我想要{deviceId：＆＃39; idvalue＆＃39;，cpuUtilization：＆＃39; value＆＃39;}

等信息

Answer 1

Edit var data="name"+get_name;至var data="name="+get_name;

检查您的响应，如果响应不在json或json无效，则发生错误