我的GetScreen
功能如下:
void GetScreen(int clientSocket, const char *filename) {
HDC hDC = NULL;
int nScreenWidth = GetSystemMetrics(SM_CXSCREEN);
int nScreenHeight = GetSystemMetrics(SM_CYSCREEN);
HWND hDesktopWnd = GetDesktopWindow();
HDC hDesktopDC = GetDC(hDesktopWnd);
HDC hCaptureDC = CreateCompatibleDC(hDesktopDC);
HBITMAP hCaptureBitmap =CreateCompatibleBitmap(hDesktopDC,
nScreenWidth, nScreenHeight);
SelectObject(hCaptureDC,hCaptureBitmap);
BitBlt(hCaptureDC,0,0,nScreenWidth,nScreenHeight,
hDesktopDC,0,0,SRCCOPY|CAPTUREBLT);
SaveBitmap(clientSocket, "test.bmp",hCaptureBitmap); //here to save the captured image to disk
**//here to send Hbitmap: send(clientSocket,?,?,Null);**
ReleaseDC(hDesktopWnd,hDesktopDC);
DeleteDC(hCaptureDC);
DeleteObject(hCaptureBitmap);
}
现在我想在没有位图保存的情况下发送HBITMAP
套接字。
我用Google搜索并找到GetDIBits
和SetDIBits
但我不知道我怎么能完全使用它。有人能帮我吗?谢谢。
现在我试图通过以下代码从HBITMAP获取BYTE:
BYTE* getPixArray(HBITMAP hBitmap)
{
HDC hdc,hdcMem;
hdc = GetDC(NULL);
hdcMem = CreateCompatibleDC(hdc);
BITMAPINFO MyBMInfo = {0};
MyBMInfo.bmiHeader.biSize = sizeof(MyBMInfo.bmiHeader);
// Get the BITMAPINFO structure from the bitmap
if(0 == GetDIBits(hdcMem, hBitmap, 0, 0, NULL, &MyBMInfo, DIB_RGB_COLORS))
{
cout<<"FAIL\n"<<endl;
}
// create the bitmap buffer
BYTE* lpPixels = new BYTE[MyBMInfo.bmiHeader.biSizeImage];
MyBMInfo.bmiHeader.biSize = sizeof(MyBMInfo.bmiHeader);
MyBMInfo.bmiHeader.biBitCount = 32;
MyBMInfo.bmiHeader.biCompression = BI_RGB;
MyBMInfo.bmiHeader.biHeight = (MyBMInfo.bmiHeader.biHeight < 0) ? (-MyBMInfo.bmiHeader.biHeight) : (MyBMInfo.bmiHeader.biHeight);
// get the actual bitmap buffer
if(0 == GetDIBits(hdc, hBitmap, 0, MyBMInfo.bmiHeader.biHeight, (LPVOID)lpPixels, &MyBMInfo, DIB_RGB_COLORS))
{
cout<<"FAIL\n"<<endl;
}
return lpPixels;
}
现在在socket的另一边我想从BYTE获得HBITMAP!?! 请帮我。 THX。
答案 0 :(得分:1)
获得HBITMAP
后,请致电HBITMAPToPixels
。发送width
,height
和bitsperpixel
。接下来发送像素..
在套接字的另一端,阅读width
,阅读height
,阅读bitsperpixel
。
然后创建一个大小为((width * Bmp.bmBitsPixel + 31) / 32) * 4 * height
的缓冲区
将那么多字节读入缓冲区并调用HBITMAPFromPixels
所讨论的功能定义如下..
#include <iostream>
#include <stdexcept>
#include <vector>
#include <cstring>
#include <memory>
#include <windows.h>
std::unique_ptr<std::remove_pointer<HBITMAP>::type, std::function<void(HBITMAP)>> HBITMAPFromPixels(const std::vector<std::uint8_t> &Pixels, std::uint32_t width, std::uint32_t height, std::uint16_t BitsPerPixel)
{
BITMAPINFO Info = {0};
std::memset(&Info, 0, sizeof(BITMAPINFO));
Info.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
Info.bmiHeader.biWidth = width;
Info.bmiHeader.biHeight = -height;
Info.bmiHeader.biPlanes = 1;
Info.bmiHeader.biBitCount = BitsPerPixel;
Info.bmiHeader.biCompression = BI_RGB;
Info.bmiHeader.biSizeImage = ((width * BitsPerPixel + 31) / 32) * 4 * height;
HBITMAP Result = CreateDIBitmap(GetDC(nullptr), &Info.bmiHeader, CBM_INIT, &Pixels[0], &Info, DIB_RGB_COLORS);
return std::unique_ptr<std::remove_pointer<HBITMAP>::type, std::function<void(HBITMAP)>>(Result, [&](HBITMAP hBmp){DeleteObject(hBmp);});
}
void HBITMAPToPixels(HBITMAP BitmapHandle, std::vector<std::uint8_t> &Pixels, std::uint32_t &width, std::uint32_t &height, std::uint16_t &BitsPerPixel)
{
if (BitmapHandle == nullptr)
{
throw std::logic_error("Null Pointer Exception. BitmapHandle is Null.");
}
Pixels.clear();
BITMAP Bmp = {0};
BITMAPINFO Info = {0};
HDC DC = CreateCompatibleDC(nullptr);
std::memset(&Info, 0, sizeof(BITMAPINFO));
HBITMAP OldBitmap = (HBITMAP)SelectObject(DC, BitmapHandle);
GetObject(BitmapHandle, sizeof(Bmp), &Bmp);
Info.bmiHeader.biSize = sizeof(BITMAPINFOHEADER);
Info.bmiHeader.biWidth = width = Bmp.bmWidth;
Info.bmiHeader.biHeight = height = Bmp.bmHeight;
Info.bmiHeader.biPlanes = 1;
Info.bmiHeader.biBitCount = BitsPerPixel = Bmp.bmBitsPixel;
Info.bmiHeader.biCompression = BI_RGB;
Info.bmiHeader.biSizeImage = ((width * Bmp.bmBitsPixel + 31) / 32) * 4 * height;
Pixels.resize(Info.bmiHeader.biSizeImage);
GetDIBits(DC, BitmapHandle, 0, height, &Pixels[0], &Info, DIB_RGB_COLORS);
SelectObject(DC, OldBitmap);
height = height < 0 ? -height : height;
DeleteDC(DC);
}
答案 1 :(得分:1)
始终发送位图的像素数据(unsigned char *)。 HBitmap只是位图的句柄。另外要注意尺寸问题,如果你的身高,宽度和bpp很高,你需要考虑压缩像素数据。