使用C语言将1个列表的元素复制到另一个列表中

Question

我创建了一个程序，它在列表中获取10个值，然后将其存储在另一个列表中，然后显示。现在问题是代码很长。你能告诉我如何使用for循环而不是声明和使用这些变量，然后再将它们复制到列表中。

这是我的代码：

#include <stdio.h>

int main() {

int marksList1 = 0;
int marksList2 = 0;
int marksList3 = 0;
int marksList4 = 0;
int marksList5 = 0;
int marksList6 = 0;
int marksList7 = 0;
int marksList8 = 0;
int marksList9 = 0;
int marksList10 = 0;

int correctedList1 = 0;
int correctedList2 = 0;
int correctedList3 = 0;
int correctedList4 = 0;
int correctedList5 = 0;
int correctedList6 = 0;
int correctedList7 = 0;
int correctedList8 = 0;
int correctedList9 = 0;
int correctedList10 = 0;

printf("Enter Marks for Students: ");

scanf("%d", &marksList1);
scanf("%d", &marksList2);
scanf("%d", &marksList3);
scanf("%d", &marksList4);
scanf("%d", &marksList5);
scanf("%d", &marksList6);
scanf("%d", &marksList7);
scanf("%d", &marksList8);
scanf("%d", &marksList9);
scanf("%d", &marksList10);

correctedList1 = marksList1;
correctedList2 = marksList2;
correctedList3 = marksList3;
correctedList4 = marksList4;
correctedList5 = marksList5;
correctedList6 = marksList6;
correctedList7 = marksList7;
correctedList8 = marksList8;
correctedList9 = marksList9;
correctedList10 = marksList10;

printf("\n");

printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
printf("CorrectedList1: correctedList1);
}

Answer 1

你应该像这样声明了标记列表和更正列表的列表：

int i, marksList[10] = {0};
int correctedList[10] = {0};

我将向您展示如何仅为第一个列表创建for循环，然后希望您可以对第二个列表执行相同操作并打印更正的List。这是markedList的for循环：

for ( i = 0; i < 10; i++) {
    printf("Enter Marks for Student %d: ", i+1 );
    scanf("%d", &marksList[i]);
}