Question

从mysql获取时间戳它会返回类似“2014-03-19 12:00:43”的内容，而在java中我想要从时间戳和当前时间中获得差异。

java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都会实现同样的东西

date_def

java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都会实现同样的东西

date_default_timezone_set('America/New_York');
$server = timesince($row['timestamp']);

function timesince($time){
    $seconds = strtotime($time) - time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;

java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都可以实现 java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都会实现同样的东西

date_default_timezone_set('America/New_York');
$server = timesince($row['timestamp']);

java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都会实现同样的东西

date_default_timezone_set('America/New_York');
$server = timesince($row['timestamp']);

function timesince($time){
    $seconds = strtotime($time) - time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;

function timesince($time){
    $seconds = strtotime($time) - time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;
    $seconds = strtotime($time) - time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;ault_timezone_set('America/New_York');

java的新手并且非常陌生，这里是我在php中所拥有的......任何类似的东西都会实现同样的东西

date_default_timezone_set('America/New_York');
$server = timesince($row['timestamp']);

function timesince($time){
    $seconds = strtotime($time) - time();
    $days = floor($seconds/ -86400);
    $seconds %= 86400;
    $minutes = floor($seconds / -60);
    $seconds %= 60;
    $seconds *= -1;

    if ($days > 360){
        return "Not voted here yet.";
    }

    if($days > 1){
        $days = $days." days, ";
    } elseif ($days == 1){
        $days = $days." day, ";
    } else {
        $days  = "";
    }
    if($hours > 1){
        $hours = $hours." hours, ";
    }elseif ($hours == 1){
        $hours = $hours." hour, ";
    } else {
        $hours  = "";
    }
    if($minutes > 1){
        $minutes = $minutes." minutes and ";
    }elseif ($minutes == 1){
        $minutes = $minutes." minute and ";
    }else {
        $minutes  = "";
    }
    if($seconds > 1){
        $seconds = $seconds." seconds";
    }elseif ($seconds == 1){
        $seconds = $seconds." second";
    }

    return $days.$hours.$minutes.$seconds." ago";
}

我在java中看不到与strtotime类似的东西，也不想使用任何其他库。

另外在php脚本中我有顶部

date_default_timezone_set('America/New_York');

所以它与时区的关系得到了正确的时间差异。

从哪里开始在java中做类似的事情？

Answer 1

Javascript的原生Date对象能够非常轻松地复制php的strtodate功能。要调用它，您只需使用：

var d = new Date(dateString);

（有关更多信息，请参阅http://www.w3schools.com/jsref/jsref_obj_date.asp）所以你可以使用如下函数：

function timesince( dateString ) {
    var originalTime = new Date();          // The time you provided in milliseconds converted to javascript object
    var currentTime = new Date();                       // The current time as a javascript object
    return millisecondDifference = parseFloat(currentTime.getTime()) - parseFloat(originalTime.getTime());
    // returns the difference in milliseconds between the current time and the original time
    // parseFloat is used to ensure that the values returned are read by javascript as floats (numbers) and thus can have math operations performed on them
}

以毫秒为单位返回差异。然后，如果您想将其转换为＆＃34; Human Readable＆＃34;格式，您可以使用新的Date对象，如下所示：

var diffRaw = timesince( '2014-03-19 12:00:43' );
var diff = new Date(diffRaw);
var seconds = diff.getSeconds() // Seconds from 0 - 59
var minutes = diff.getMinutes() // Minutes from 0 - 59
var hours = diff.getHours()     // Hours from 0 - 23
var day = diff.getDay()         // Days from 0 - 6
var date = diff.getDate()       // Date from 1 - 31
var month = diff.getMonth()     // Months from 0 - 11
var year = diff.getFullYear()   // XXXX year starting from 1970

要复制您准确编写的功能，可以使用以下功能：

function timesince( dateString ) {
    var originalTime = new Date(dateString);
    var currentTime = new Date();
    var diffRaw = millisecondDifference = parseFloat(currentTime.getTime()) - parseFloat(originalTime.getTime());
    var diff = new Date(diffRaw);
    var seconds = diff.getSeconds();
    var minutes = diff.getMinutes();
    var hours = diff.getHours();
    var day = diff.getDay();
    var date = diff.getDate() - 1;
    var month = diff.getMonth();
    var year = diff.getFullYear();

    if( year !== 1970 ) {
        return "Not voted here yet.";
    }

    var returnString = "";
    if(month > 1 || month == 0) {
        returnString += month + " months, ";
    } else {
        returnString += month + " month, ";
    }

    if(date > 1 || date == 0) {
        returnString += date + " days, ";
    } else {
        returnString += date + " day, ";
    }

    if(hours > 1 || hours == 0) {
        returnString += hours + " hours, ";
    } else {
        returnString += hours + " hour, ";
    }

    if(minutes > 1 || minutes == 0) {
        returnString += minutes + " minutes, ";
    } else {
        returnString += minutes + " minute, ";
    }

    if(seconds > 1 || seconds == 0) {
        returnString += seconds + " seconds, ";
    } else {
        returnString += seconds + " second, ";
    }

    return returnString;
}

你可以在这里找到一个有效的例子： http://jsfiddle.net/MQPPw/

Answer 2

不要用Java（或PHP）来做这件事。这是在MySQL中使用date/time functions。

完成的

SELECT UNIX_TIMESTAMP() - UNIX_TIMESTAMP(my_timestamp_col) AS seconds_ago ...

第一种方法将当前时间返回为unix timestamp（即，自纪元以来的秒数）。第二种方法将my_timestamp_col时间作为unix时间戳返回。减去这两个，你有几秒钟前my_timestamp_col。

编辑：正如亚历山大指出的那样，当你考虑时区时，这会变得更加复杂。一种方法是使用CONVERT_TZ函数将my_timestamp_col转换为UTC，然后在其上调用UNIX_TIMESTAMP：

UNIX_TIMESTAMP(CONVERT_TZ(timestamp, '-5:00', '+0:00'))

另一个选择是在Java端执行此操作：将字段设置为Date，应该为您进行时区转换;然后调用其getTime()方法从纪元开始获取毫秒，并从System.currentTimeMillis()中减去该值。这可以告诉你事件发生了多少毫秒。

Java时差

2 个答案: