我正在尝试处理后台的图片加载。
现在,我看一下下一个链接 - here
我有一些我不明白的事情 -
1)我为listview项目制作了下一个CursorAdapter -
public class ChatCursorAdapter extends CursorAdapter implements OnClickListener {
public ChatCursorAdapter(Context context, Cursor c) {
super(context, c, 0);
}
@Override
public int getCount() {
return getCursor() == null ? 0 : super.getCount();
}
@Override
public int getViewTypeCount() {
return 2;
}
@Override
public int getItemViewType(int _position) {
Cursor cursor = (Cursor) getItem(_position);
return getItemViewType(cursor);
}
private int getItemViewType(Cursor cursor) {
String sender = cursor.getString(2);
SharedPreferences userPref = PreferenceManager
.getDefaultSharedPreferences(MainChat.this);
String saveUser = userPref.getString("user", "");
if (saveUser.equalsIgnoreCase(sender)){
return 0;
}else{
return 1;
}
}
@Override
public void bindView(View view, Context context, Cursor cursor) {
holder = (ViewHolder) view.getTag();
holder.mesg.setText(getSmiledText(MainChat.this,msg));
holder.mesg2.setText(getSmiledText(MainChat.this,msg2));
holder.myImage.setTag(picPath);
holder.myImage.setImageBitmap(setImageToImageView(picPath));
}
@Override
public View newView(Context context, Cursor cursor, ViewGroup parent) {
ViewHolder holder = new ViewHolder();
View itemLayout = null;
switch(getItemViewType(cursor)){
case 0:
itemLayout = getLayoutInflater().inflate(R.layout.msg_item1,parent, false);
break;
case 1:
itemLayout = getLayoutInflater().inflate(R.layout.msg_item13, parent,false);
break;
}
itemLayout.setTag(holder);
holder.mesg = (TextView) itemLayout.findViewById(R.id.text_start);
holder.mesg2 = (TextView) itemLayout.findViewById(R.id.text_end);
holder.myImage = (ImageView) itemLayout.findViewById(R.id.imageView_msgpic);
return itemLayout;
}
现在我想使用链接中的信息。
但是我不明白 - 我需要传递给AsrsorTask并在CursorAdapter中留下什么?
示例代码也使用 -
.execute(holder);
我不能像这样调用AsyncTask -
new AsyncTask().execute();
我应该如何以及在哪里调用AsyncTask,我不明白吗?
感谢您提供任何帮助
答案 0 :(得分:0)
你总是可以使用像Universal-Image-Loader或Picasso这样的外部库来实现你想要做的事情=)
答案 1 :(得分:0)
看看AsyncTask。您必须覆盖doInBackground方法。您可以定义构造函数以提供要放置下载图像的视图。
public class ImageDownloader extends AsyncTask<String, Void, List<Bitmap>> {
private ImageView ivImageHolder;
private Context context;
public ImageDownloader(Context context, ImageView imageHolder) {
this.ivImageHolder = imageHolder;
this.context = context;
}
...
@Override
protected List<Bitmap> doInBackground(String... params) {
//This happens in background
List<Bitmap> bitmaps = new ArrayList<Bitmap>();
for (String url : params) {
Bitmap bitmap = DownloadImage(url);
bitmaps.add(bitmap);
}
return bitmaps;
}
....
private Bitmap DownloadImage(String URL) {
Bitmap bitmap = null;
InputStream in = null;
try {
in = OpenHttpConnection(URL);
bitmap = BitmapFactory.decodeStream(in);
in.close();
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
return bitmap;
}
...
private InputStream OpenHttpConnection(String urlString) throws IOException {
InputStream in = null;
int response = -1;
URL url = new URL(urlString);
URLConnection conn = url.openConnection();
if (!(conn instanceof HttpURLConnection))
throw new IOException("Not an HTTP connection");
try {
HttpURLConnection httpConn = (HttpURLConnection) conn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
response = httpConn.getResponseCode();
if (response == HttpURLConnection.HTTP_OK) {
in = httpConn.getInputStream();
}
} catch (Exception ex) {
throw new IOException("Error connecting");
}
return in;
}
@Override
protected void onPostExecute(List<Bitmap> bitmaps) {
super.onPostExecute(bitmaps);
for (int i = 0; i < bitmaps.size(); i++) {
final Bitmap bitmap = bitmaps.get(i);
ivImageHolder.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
new ImageViewActivity(context, bitmap).show();
}
});
// iv.setImageBitmap(bitmap);
ivImageHolder.setImageBitmap(bitmap);
ivImageHolder.setVisibility(ImageView.VISIBLE);
}
}
答案 2 :(得分:0)
如果你写了asyntask方法,我可以说你怎么能用它,如果它需要字符串值 你可以像这样使用:
new your_async(context).execute(url) ;
但是在我的建议中:你应该使用lazyadapter在listview上使用位图,因为如果不注意图像的属性,就会出现一个记忆问题。 这是链接:stackoverfow