Question

我正在将一些查询滚动到存储过程中并且遇到了#1327 - Undeclared variable错误......但奇怪的是，它声称未声明的变量实际上是表名。

解决问题

所以我提取了它崩溃的程序位，并尝试通过PHPMyAdmin直接在数据库上运行它作为正常的SQL查询......同样的事情。经过多次修修补补后，我似乎正在加入另一张桌子。

如果我在一个表上运行查询，那很好，就像这样：

SET @i_channel_id = 3;
SET @i_product_id = 90;

SELECT 
`product_status_to_channel`.`status_code` INTO @s_status_code

FROM `product_status_to_channel`

WHERE `product_status_to_channel`.`channel_id` = @i_channel_id
AND `product_status_to_channel`.`product_id` = @i_product_id

ORDER BY IF(`product_status_to_channel`.`date` IS NULL, 1, 0) ASC, 
    `product_status_to_channel`.`date` DESC

LIMIT 0, 1;

SELECT @s_status_code AS status_code;

哪个输出'LIVE'作为PHPMyAdmin中的status_code - 这很好。

但是，当我尝试JOIN到消息表以查找关联的状态消息时，我收到错误：#1327 - Undeclared variable: product_status_to_channel_lang ...但是product_status_to_channel_lang是一个表？！< / p>

SET @i_channel_id = 3;
SET @i_language_id = 3;
SET @i_product_id = 90;

SELECT 
`product_status_to_channel`.`status_code` INTO @s_status_code,
`product_status_to_channel_lang`.`string` INTO @s_status_message

FROM `product_status_to_channel`

LEFT JOIN `product_status_to_channel_lang`
    ON `product_status_to_channel`.`product_status_to_channel_id` = `product_status_to_channel_lang`.`product_status_to_channel_id`
    AND `product_status_to_channel_lang`.`language_id` = @i_language_id

WHERE `product_status_to_channel`.`channel_id` = @i_channel_id
AND `product_status_to_channel`.`product_id` = @i_product_id

ORDER BY IF(`product_status_to_channel`.`date` IS NULL, 1, 0) ASC, `product_status_to_channel`.`date` DESC

LIMIT 0, 1;

SELECT @s_status_code AS status_code, @s_status_message AS status_message;

它是否试图将product_status_to_channel_lang.product_status_to_channel_id评估为JOIN上的变量？

LEFT JOIN `product_status_to_channel_lang`
    ON `product_status_to_channel`.`product_status_to_channel_id` = `product_status_to_channel_lang`.`product_status_to_channel_id`

我想我忽略了一些明显的东西？

我在两个方面都试过这个：

使用MySQL 5.5.27运行xampp的Win7盒--MySQL社区服务器（GPL）
运行MySQL的Debian盒子5.1.73-1-log - （Debian）

Answer 1

没关系 - 这是显而易见的事情：

SELECT 
`product_status_to_channel`.`status_code` INTO @s_status_code,
`product_status_to_channel_lang`.`string` INTO @s_status_message

应该是：

SELECT 
`product_status_to_channel`.`status_code`, 
`product_status_to_channel_lang`.`string` 

INTO 
@s_status_code, 
@s_status_message

......一定是星期五，花了几个小时就看到了。

... INTO @s_status_code,
`product_status_to_channel_lang`.`string` ...

^这就是它试图将product_status_to_channel_lang指定为放置数据的变量。

＃1327 - 未声明的变量：table_name

1 个答案: