Question

我正在尝试使用数组并将其合并到一个字典数组中，但不确定如何执行此操作。

我有一系列字典，如下所示：

(
        {
        caption = a;
        urlRep = "12";
    },
        {
        caption = b;
        urlRep = "34";
    },
        {
        caption = c;
        urlRep = "56";
    }
)

并给出一个这样的数组：

(12,34,56,78)

我想将它合并到我的词典中，使它看起来像这样：

(
        {
        caption = a;
        urlRep = "12";
    },
        {
        caption = b;
        urlRep = "34";
    },
        {
        caption = c;
        urlRep = "56";
    },
        {
        caption = "";
        urlRep = "78";
    }
)

修改我还需要考虑从dicts数组中删除给定数组是否包含urlReps之一。

任何帮助都会非常感激，因为我一直试图弄清楚这一点。

Answer 1

这是一个简单，高效，优雅的解决方案，使用NSSet来处理唯一键：

NSMutableArray *arrayOfDicts;    // your input array of dictionaries
NSArray *urlRepArray;            // the new array with string elements

// create a set of potentially new keys (urlReps)
NSMutableSet *urlReps = [NSMutableSet setWithArray:urlRepArray];

// remove existing keys from your original array
[urlReps minusSet:[NSSet setWithArray:[arrayOfDicts valueForKey:@"urlRep"]]];

// merge new dicts to the original array
for (id urlRep in urlReps)
    [arrayOfDicts addObject:@{ @"urlRep" : urlRep, @"caption" : @"" }];

Answer 2

最简单的AFAIK方式，使用valueForKeyPath过滤

//Your array of dictionary I created here for debugging purpose.
NSArray *tmpArray = @[ @{@"caption":@"a",@"urlRep":@"12"},
                       @{@"caption":@"b",@"urlRep":@"34"},
                       @{@"caption":@"c",@"urlRep":@"56"}];

//This will give you 12,34,56 in your case
NSArray *existingURLRep = [tmpArray valueForKeyPath:@"urlRep"]; 

NSMutableArray *targetArray = [[NSMutableArray alloc] initWithObjects:@12, @34,@56, @78, nil]; //Assuming you have your array as you said
[targetArray removeObjectsInArray:existingURLRep];
//remove existing items  you will have 78 here now loop through 
//this targetArray and add it to your array of dictionary.

Answer 3

（无效）filterArray {

NSLog（@＆＃34;过滤前的数组=％@＆＃34;，initialArray）; NSLog（@＆＃34;给定Array =％@＆＃34;，givenArray）;

NSMutableSet * urlReps = [NSMutableSet setWithArray：givenArray];

//删除现有记录 [urlReps minusSet：[NSSet setWithArray：[initialArray valueForKey：@＆＃34; urlRep＆＃34;]]];

//添加新对象 for（id obj in urlReps）{ [initialArray addObject：@ {@＆＃34; caption＆＃34;：@＆＃34;＆＃34;，@＆＃34; urlRep＆＃34; ：obj}]; }

//删除对象 NSMutableSet * set = [[NSMutableSet alloc] init];

for（initialArray中的id obj）{ NSDictionary * dict =（NSDictionary *）obj; NSPredicate * predicate = [NSPredicate predicateWithFormat：@＆＃34; self =％@＆＃34;，dict [@＆＃34; urlRep＆＃34;]]; NSArray * filteredArray = [givenArray filteredArrayUsingPredicate：predicate]; if（filteredArray.count == 0）{ [set addObject：dict]; } }

[initialArray removeObjectsInArray：[set allObjects]];

NSLog（@＆＃34;过滤后的数组=％@＆＃34;，initialArray）; }

Answer 4

NSMutableArray *yourArray;//This will be your original array of dictionary.
NSArray *newArray;//This is your new array which you want to add.
for(id obj in newArray) {
NSPredicate *predicate = [NSPredicate predicateWithFormat:@"urlRep = %@", id];
NSArray *filteredArray = [locationsArray filteredArrayUsingPredicate:predicate];
if(filteredArray.count == 0) {
    [yourArray addObject:@{@"caption":@"", @"urlRep" : id}];
}
}

Answer 5

/*
NSArray *inputArray;//(12,34,56,78)- I assumes you are having array which contains strings. If you are having number then modify the code as you needed

NSMutableArray *colloectionArray;// your total collection

NSMutableArray *tobeMerged;
*/

// Extract the dictionary set only to be merged
for (NSString* aNumber in inputArray) {

    for (NSDictionary *aItem in colloectionArray) {

        NSString *urlRep= [aItem valueForKey:@"urlRep"];

        if (![urlRep isEqualToString:aNumber]) {
            [tobeMerged addObject:urlRep];
        }
    }

}

// Add missed items in collection
for (NSString *aNumber in tobeMerged) {

    NSMutableDictionary *newset = [[NSMutableDictionary alloc]init];
    [newset setObject:@"" forKey:@"caption"];
    [newset setObject:aNumber forKey:@"urlRep"];

    [colloectionArray addObject:newset];

}

将数组合并到字典中

5 个答案: