Question

这是我搜索部分的代码，但它不起作用。你能给我一些帮助吗？我是编程的新手，我真的很喜欢指针。感谢。

typedef struct Dictionary_Entry{
    int index;
    char character[100];
    struct Dictionary_Entry *link;
}Dictionary_Entry;

typedef struct Dictionary{
    Dictionary_Entry *top;
}Dictionary;

int check_in_dictionary(Dictionary *dictionary, char string[100], char file_char[100]){
    Dictionary_Entry *runner = dictionary->top;
    strcat(string, file_char);
        while(runner != NULL){
            if((strcmp(string, runner->character)) == 0){
                break;
                return runner->index;
            }
        }
        return -1;
}

Answer 1

break关键字离开循环，因此您的return runner->index行不会被执行。交换两行（或删除break，因为return 也离开循环，然后你应该没问题。

Answer 2

以下是我的评论以////

开头的更正版本

int check_in_dictionary(Dictionary *dictionary, char string[100], char file_char[100]){
    Dictionary_Entry *runner = dictionary->top;
    strcat(string, file_char);
    while(runner != NULL){
      if((strcmp(string, runner->character)) == 0){
         return runner->index;  // found
         //// break not neccessary here as return returns anyway
      }
      runner = runner->link ;  //// goto next entry
    }
    return -1;
}

BTW strcat(string, file_char);不是必需的，您可以直接与file_char进行比较strcmp(file_char, runner->character)

Answer 3

您需要在while循环中扫描Dictionary。像这样的东西：

 while(runner != NULL){
        if((strcmp(string, runner->character)) == 0){
            return runner->index;
        }
    runner = runner->next; /* go to next element in dictionary */
    }

在堆栈中搜索

3 个答案: