Question

我有一个带有两个用于数据输入的微调器的活动。

我还有一个带有代码的按钮，用于将所选项目值插入数据库。

我还添加了代码，以便在数据成功添加到数据库后从微调器中删除该项。

问题在于，这是第一次成功。

如果我选择其他项目，填写其他所需数据并单击要添加的按钮，我仍然会获得成功添加的上一项的ID。我已经添加了逻辑来防止这种情况发生，从而失败了。

关闭活动并重新启动后，它再次起作用... 以下是代码。

public void Add(View v)
    {
        // get tenant id
        // check whether appartment occupied ...and still active
        // check tenants..if same tenant? ask whether want to renew and end previous tenacy
        // test overlapping tenancy
        int pos= spinner.getSelectedItemPosition();
        TenantList tenant= (TenantList)t.get(pos);
        // get tenant id
        int tenant_id= tenant.get_id();
        int pos1= spinner1.getSelectedItemPosition();
        Apartments a = (Apartments)b.get(pos1);
        //get apartment id
        int apartment_id= a.get_id();
        // tenant has a valid tenancy
        if(db.HasValidTenancy(tenant_id)==true)
        {
            // inform user and exit
                        // make a toast
                                    Context context = this.getApplicationContext();         
                                    CharSequence msg ="This Tenant has a vaild running teanancy"+ "\n"+
                                                      "If the tenancy  has expired  first make it  expired"+ "\n"+
                                                       "Before creating a new tenancy";
                                    int duration =Toast.LENGTH_LONG;
                                    Toast toast = Toast.makeText(context, msg, duration);
                                    toast.setGravity(Gravity.CENTER, 0, 0);
                                    toast.show();
                                    return;
        }

        // apartment free?

        if(db.ApartmentNotFree(apartment_id)==true)
        {
            // inform user and exit
            // make a toast
                        Context context = this.getApplicationContext();         
                        CharSequence msg ="This apartment not free"+ "\n"+
                                          "If the tenant left, first teminate the Tenancy";
                        int duration =Toast.LENGTH_LONG;
                        Toast toast = Toast.makeText(context, msg, duration);
                        toast.setGravity(Gravity.CENTER, 0, 0);
                        toast.show();
                        return;

        }
        // is same tenant?

         Date sdate=null;
         Date edate=null;
        try {
             sdate = fm.parse(txtviewstartdate.getText().toString());
        } catch (ParseException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }
        try {
         edate =fm.parse( txtvieweenddate.getText().toString());
        } catch (ParseException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        String startdate = fm.format(sdate);
        String enddate =fm.format(edate);
        EditText rental= (EditText)
                findViewById(R.id.editTextRental);
            // test rent ented
        if(rental.getText().toString().length()==0)
        {
            // inform user and exit
            // make a toast
                        Context context = this.getApplicationContext();         
                        CharSequence msg ="You must enter the Monthly Rental amount";                                         
                        int duration =Toast.LENGTH_LONG;
                        Toast toast = Toast.makeText(context, msg, duration);
                        toast.setGravity(Gravity.CENTER, 0, 0);
                        toast.show();
                        return;
        }
        double rent = Double.parseDouble(rental.getText().toString());

        db.AddTenancy(tenant_id, apartment_id, startdate, enddate, rent, 0);
        // can u refresh data on spinners?
        // remove apartment
        // remove tenant
        tenantlist.remove(pos);
        apartments.remove(pos1);
        dataAdapter.notifyDataSetChanged();
        dataAdapter1.notifyDataSetChanged();

    }

有什么想法吗？或者我需要在上面的代码中重新启动Activity？

罗纳德

Answer 1

您将从名为t和b的列表中获取租户和公寓：

TenantList tenant= (TenantList)t.get(pos);
Apartments a = (Apartments)b.get(pos1);

但是你要将它们从名为tenanlist和apartments的不同列表中删除：

tenantlist.remove(pos);
apartments.remove(pos1);

如果必须

，您应该使用相同的列表，或从两者中删除它

用于数据输入的微调器有问题

1 个答案: