我有桌子
id | industry_id | type | key
1 1 0 word1
2 1 1 word2
3 1 0 word3
4 1 1 word4
5 2 0 word5
6 2 1 hello
7 2 0 world
结果我需要得到表
industry_id | title | description
1 | word1 word3 | word2 word4
2 | word5 world | hello
这意味着所有类型为0的单词都会转到title,类型1指向描述
现在我几乎可以得到我想要的查询(但每个行业仍然可以获得2条记录)
SELECT industry_id, type, GROUP_CONCAT(`key` SEPARATOR ' ') AS TEXT FROM table GROUP BY industry_id, type
答案 0 :(得分:0)
试试这样:
SELECT industry_id, type,
GROUP_CONCAT(if(type = 0,key,'') SEPARATOR ' ') AS title,
GROUP_CONCAT(if(type = 1,key,'') SEPARATOR ' ') AS description
FROM table GROUP BY industry_id, type
答案 1 :(得分:0)
SELECT industry_id
, MAX(CASE WHEN type = 0 THEN text END) title
, MAX(CASE WHEN type = 1 THEN text END) description
FROM
( SELECT industry_id
, type
, GROUP_CONCAT(`key` SEPARATOR ' ') TEXT
FROM my_table
GROUP
BY industry_id
, type
) x
GROUP
BY industry_id;
考虑重命名key
列!
答案 2 :(得分:0)
您按industry_id, type
分组,因此每个行业ID都会获得4行和2行尝试此操作
SELECT industry_id,
GROUP_CONCAT(CASE WHEN `type`=0 THEN `key` END SEPARATOR ' ') AS title,
GROUP_CONCAT(CASE WHEN `type`=1 THEN `key` END SEPARATOR ' ') AS description
FROM Table1
GROUP BY industry_id