Question

我的要求是在提交表单时向表单提交表单下拉列表，同时提交表单必须检查是否选择了燃料类型我从数据库获得燃料类型我的代码在视图中

public function create_vehicle_ad()
{
       $this->form_validation->set_rules('js_Fuel_Type', 'Fuel Type', 'required|is_natural');
      if($this->form_validation->run()== FALSE)
        {
    $data['fuel_type'] = $this->create_ad->getFuelType();
       $this->load->view('create_vehicle_ad',$data);
          }
}

我的模型代码

public function getFuelType()
{
    $this->db->select('Fuel');
    $this->db->from('ref_vehicle_fuel_type'); 
    $query = $this->db->get();
    $data=array();
    $data[0]='SELECT';
     foreach($query->result_array() as $row){
       $data[$row['Fuel']]=$row['Fuel'];
    }
    return $data;
}

我在视野中的代码

<div class="form-group">
    <label class="control-label col-md-3 mail-text" for="select"><span class="star">*</span>Fuel Type :</label>
    <div class="col-md-3">
                <?php 
                         $js = 'id = "js_Fuel_Type" class="form-control"';  
                         echo form_dropdown('js_Fuel_Type',$fuel_type,set_value(js_Fuel_Type,$js_Fuel_Type,TRUE),$js);
                         echo "<span class='star'>"; echo form_error("js_Fuel_Type");echo "</span>";
                ?> 
    </div> 

    </div>

Plz提前帮助我

使用Codeigniter进行表单下拉验证

0 个答案: