Question

是否有一种方法可以为开关状态实现带有自定义图形的UISwitch？或者作为另一种选择，UIButton具有UISwitch功能？

Answer 1

UIButton已经支持“切换”功能。

只需在Interface Builder中为“选定状态配置”设置不同的图像，并使用selected的{{1}}属性切换其状态。

Answer 2

将图像设置为在选定状态下显示：

[button setImage:[UIImage imageNamed:@"btn_graphics"] forState:UIControlStateSelected];

然后在内部选择器上触摸，设置：

button.selected = YES;

如果您想要取消其他按钮的选择，请设置：

otherButton.selected = NO;

Answer 3

基于PGB和nurne上面所说的内容，在设置状态并附加选择器（事件方法）后，您可能希望将此代码放在该选择器中。

- (IBAction)cost:(id)sender 
{
    //Toggle current state and save
    self.buttonTest.selected = !self.buttonTest.selected;

    /**
     The rest of your method goes here.
     */
}

Answer 4

以编程方式倾斜：

-(void) addToggleButton {
    CGRect aframe = CGRectMake(0,0,100,100);

    UIImage *selectedImage = [UIImage imageNamed:@"selected"];
    UIImage *unselectedImage = [UIImage imageNamed:@"unselected"];

    self.toggleUIButton = [[UIButton alloc] initWithFrame:aframe];
    [self.toggleUIButton setImage:unselectedImage forState:UIControlStateNormal];
    [self.toggleUIButton setImage:selectedImage forState:UIControlStateSelected];
    [self.toggleUIButton addTarget:self 
                            action:@selector(clickToggle:) 
                  forControlEvents:UIControlEventTouchUpInside];
    [self addSubview:self.toggleUIButton];
}

-(void) clickToggle:(id) sender {
    BOOL isSelected = [(UIButton *)sender isSelected];
    [(UIButton *) sender setSelected:!isSelected];
}

具有UISwitch功能的iPhone UIButton

4 个答案: