Question

我一直在尝试使用mysql prepare语句插入多个插入条目。但是，它没有发生。

PREPARE stmt1 FROM 
'Insert into bookingdetails 
VALUES
(?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5),
(?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5)';
SET @a = 4;
EXECUTE stmt1 USING @a;
DEALLOCATE PREPARE stmt1;

结果是

PREPARE stmt1 FROM  'Insert into bookingdetails  VALUES (?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5), (?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5)'

0 row(s) affected Statement prepared.

请建议。

上述问题已得到解决。我有另一个。

流量。

我正在从PHP传递一个插入查询。

Insert into bm VALUES(?,'2014-03-11')

根据PREPARE STATEMENT友好格式化上述插入。 var_bm变量是stored_procedure的IN参数，其IN值是从PHP插入的。

set xbmquery=(select concat("'",replace(var_bm,"'", "\\'"),"\'\;"));

Output
'Insert into bm VALUES(?,\'2014-03-11\')';

以下是存储过程中的prepare语句。

PREPARE stmt1 FROM 'Select xbmquery';
SET @a = 16;
EXECUTE stmt1 USING @a;
DEALLOCATE PREPARE stmt1;

数据未插入相应的表中。请让我知道我的错误。

Answer 1

您有两个占位符，因此您必须使用USING传递两个值

EXECUTE stmt1 USING @a, @a;
                    ^^^^^^

这是 SQLFiddle 演示

Answer 2

你必须绕过作为其他字符串一部分的字符串的单引号您还错过了第二个参数的值。

更改：

PREPARE stmt1 FROM 
'Insert into bookingdetails 
VALUES
(?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5),
(?,''2014-03-12'',''sl1'',3,''GA'',12.5,37.5)';
SET @a = 4;
EXECUTE stmt1 USING @a;
DEALLOCATE PREPARE stmt1;

致：

PREPARE stmt1 FROM 
'Insert into bookingdetails 
VALUES
(?,\'2014-03-12\',\'sl1\',3,\'GA\',12.5,37.5),
(?,\'2014-03-12\',\'sl1\',3,\'GA\',12.5,37.5)';
SET @a = 4;
EXECUTE stmt1 USING @a, @a;
DEALLOCATE PREPARE stmt1;

Answer 3

尝试以下使用单引号的代码

PREPARE stmt1 FROM 
'Insert into bookingdetails 
VALUES
(?,'2014-03-12','sl1',3,'GA',12.5,37.5),
(?,'2014-03-12','sl1',3,'GA',12.5,37.5)';
SET @a = 4;
EXECUTE stmt1 USING @a, @a;
DEALLOCATE PREPARE stmt1;

Mysql准备语句多个插入

3 个答案: