### TOPOLOGY ###
class WordCountTopology < DSL::Topology
spout RandomSentenceSpout, :parallelism => 2
bolt SplitSentenceBolt, :parallelism => 2 do
source RandomSentenceSpout, :shuffle
end
bolt WordCountBolt, :parallelism => 2 do
source SplitSentenceBolt, :fields => ["word"]
end
configure :word_count do |env|
debug true
max_task_parallelism 4
if env == :cluster
num_workers 6
max_spout_pending(1000)
end
end
on_submit do |env|
if env == :local
sleep(60)
cluster.shutdown
end
end
end
### SPOUT ###
class RandomSentenceSpout < DSL::Spout
output_fields :word
on_send {@sentences[rand(@sentences.length)]}
sleep(10)
on_init do
@sentences = [
"the cow jumped over the moon",
"an apple a day keeps the doctor away",
"four score and seven years ago",
"snow white and the seven dwarfs",
"i am at two with nature"
]
end
end
#### SplitSentenceBolt ###
class SplitSentenceBolt < DSL::Bolt
output_fields :word
on_receive {|tuple| tuple[0].split(' ').map{|w| [w]}}
end
### WORDCOUNTBOLT ###
class WordCountBolt < DSL::Bolt
output_fields :word, :count
on_init {@counts = Hash.new{|h, k| h[k] = 0}}
on_receive do |tuple|
word = tuple[0].to_s
@counts[word] += 1
[word, @counts[word]]
end
end
我想实现一个tick元组。我想每60秒做一次单词计数,发出结果,将计数器重置为0。
//可能是 //在分句语句中
每隔60秒发送一次tick_tuple的功能
//在字数螺栓中
如果(tick_tuple){
发出结果
@counts = [] #re initialize
}
任何人都可以帮我实现吗?我是风暴世界的新手。
答案 0 :(得分:1)
您可以使用Storm内部tick元组功能来设置一个螺栓,以指定的间隔接收一个tick元组。
在拓扑定义的bolt部分中,只需添加以下配置:
bolt MyBolt do
...
set Backtype::Config::TOPOLOGY_TICK_TUPLE_FREQ_SECS, 60
...
end
在你的螺栓中,你可以测试这样的滴答元组:
if tuple.source_stream_id == "__tick"
...
end
答案 1 :(得分:0)
不知道红宝石,但希望python
会帮助你解决问题。这就是我们如何在我们的螺栓中使用它:
def process(self, tup):
"""
If spout trigers tick-tuple, then perform upload
"""
if tup.stream == '__tick':
self.perform_upload()
storm.ack(tup)
return