Question

例如，我有这三个列表：

r0 = ['X', 'O', 'O'] 
r1 = ['X', 'X', 'O']
r2 = ['X', '.', 'O']

我想使用像这样的循环：

n = 0    
while n < 3:
    if r0[n] == r1[n] == r2[n] == "X":
        result = "X"
        break
    elif rn[0] == rn[1] == rn[2] == "O":
        result = "O"
        break

我需要rn r0 n == 0，r1 n == 1等等。

有办法做到这一点吗？

Answer 1

你只想要：

for n, rn in enumerate((r0, r1, r2)):

通常，我认为将结构更改为列表列表会更好：

r = [['X', 'O', 'O'],
     ['X', 'X', 'O'],
     ['X', '.', 'O']]

然后你的循环是：

for n, rn in enumerate(r):

Answer 2

你的意思是：

r = [r0, r1, r2]
for n, rn in enumerate(r):
    if r0[n] == 'X' and r1[n] == 'X' and r2[n] == 'X':
        result = 'X'
        break
    elif rn[0] == 'O' and rn[1] == 'O' and rn[2] == 'O':
        result = 'O'
        break

也许更整洁：

rows = [['X', 'O', 'O'],
        ['X', 'X', 'O'],
        ['X', '.', 'O']]

for n, row in enumerate(rows):
    if all(row[n] == 'X' for row in rows):  # shadowing 'row' here, not sure what else you might call it
        result = 'X'
        break
    elif all(r == 'O' for r in row):
        result = 'O'
        break

如何检查与当前n值匹配的编号列表？

2 个答案: