Question

当我运行此查询时：

select prnt_c_fam_id as PRNT_C_FAM_ID3, min(ptel_d_redet_due) as Date_DUE
  from ptel t
 where ptel_d_redet_due > (select max(rest_d)
                             from   rest 
                            where  prnt_c_fam_id = t.prnt_c_fam_id
                              and rest_c in ('RS'))
group by prnt_c_fam_id 
order by prnt_c_fam_id

查询成功返回。当我在它周围添加括号时：

(select prnt_c_fam_id as PRNT_C_FAM_ID3, min(ptel_d_redet_due) as Date_DUE
   from ptel t
  where ptel_d_redet_due > (select max(rest_d)
                             from   rest 
                            where  prnt_c_fam_id = t.prnt_c_fam_id
                              and rest_c in ('RS'))
 group by prnt_c_fam_id 
 order by prnt_c_fam_id)

我得到了ORA00907：错过了正确的Paranthesis错误。谁知道为什么？（注意：此查询需要括号，因为它成为较大查询的from子句中的子查询。其他子查询在单独运行时使用和不使用括号。）

Answer 1

如果您将它用作子查询，请删除order by子句。子查询应如下所示。

      (
       select prnt_c_fam_id as PRNT_C_FAM_ID3, min(ptel_d_redet_due) as Date_DUE
       from ptel t
       where ptel_d_redet_due > (select max(rest_d)
       from   rest 
       where  prnt_c_fam_id = t.prnt_c_fam_id
       and rest_c in ('RS'))
       group by prnt_c_fam_id 
      )

ORA00907：缺少右括号

1 个答案: