我的应用程序中有2个页面将布局相同。我想为每个视图使用相同的视图,并通过控制器传递内容。如何在我的控制器中进行设置:
这是我的导航部分外观:
@{
Dictionary<string, string> links = new Dictionary<string,string>();
links.Add("home", "Index");
links.Add("neurosurgical", "Neurosurgical");
links.Add("pain management", "PainManagement");
links.Add("staff", "Staff");
links.Add("patient resources", "PatientResources");
links.Add("contact", "Contact");
}
<nav id="main_menu">
<ul class="primary_menu">
@foreach(var link in links)
{
<li class="@(link.Value == ViewContext.RouteData.Values["Action"].ToString() ? "active" : "")">
@Html.ActionLink(link.Key, link.Value)
</li>
}
</ul>
</nav>
上面列出的类似页面是NeuroSurgical和PainManagement。我的控制器现在看起来像这样:
namespace ****************.Controllers // Namespace redacted
{
public class HomeController : Controller
{
public ActionResult Index()
{
ViewBag.Message = "Modify this template to jump-start your ASP.NET MVC application.";
return View();
}
public ActionResult About()
{
ViewBag.Message = "Your app description page.";
return View();
}
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View();
}
}
}
About
是我设置的视图文件,用作两个页面的模板。我是否为每个页面创建操作并将它们指向About.cshtml?怎么样?
答案 0 :(得分:5)
public ActionResult Contact()
{
ViewBag.Message = "Your contact page.";
return View("About");
}
答案 1 :(得分:2)
您需要为每个页面创建操作并让它们使用相同的视图。像这样:
public ActionResult NeuroSurgical()
{
//create your model, etc here
return View("SharedViewNameHere", model);
}
public ActionResult PainManagement()
{
//create your model, etc here
return View("ViewNameHere", model);
}