Question

我试图让这个循环起作用，但它只是拒绝工作。非常感谢任何帮助。

while player1_score < 100 and player2_score < 100 and player3_score < 100 and player4_score < 100:    
    while player_turn != playerholder:
        dice_rolling()
        scoring()
        score_awarding()
        player_turn = player_turn + 1
    if player_turn == playerholder:
        player_turn == 1

我想要做的是获得在场球员的数量（球员），然后让球员在其范围内转弯，即重复直到有人获得100分或更高的分数。只要问你是否需要更多代码:) 提前谢谢。

编辑：每个人似乎都对我的要求感到困惑所以我会尝试更精细地解释它。

所以游戏中有2到4名玩家，而他们想要做的就是获得100分或更高分。由于有多个玩家，我想尝试重复结构，以有效地使用我一遍又一遍创建的功能。使用当前代码，它将为玩家提供类似的评分，直到最后一个玩家，代码完全停止并且不显示任何内容。我想做的是让代码无限重复，直到获得所需的分数，因为它将在没有错误的情况下继续骑行。我尝试了多次不同的循环，但我无法让它工作。希望这对每个人来说都更清楚一些。抱歉，无组织/不清楚的问题，对StackOverflow来说相对较新。

编辑：问题已经解决

Answer 1

顺便说一句，你应该让你的玩家保持某种列表并迭代它们，允许他们每个人在他们的迭代中转向。类似的东西：

players = [player1,player2,player3,player4]

for player in players:
    if player.score >= 100: win(player)
    dice_rolling()
    player.score += scoring()

但是，当然，只有在代码中有某种class Player时才能使用它（你应该这样做）。

class Player(object):
    def __init__(self,name):
        self.name = name
        self.score = 0
    # what else does a Player do?

实际上你也可以成为一个Game课程。

class Game(object):
    def __init__(self,players):
        self.players = players # a list of players
        self.running = False
    def dice_rolling(self):
        diceroll = sum(random.randint(1,6) for _ in range(2))
    def scoring(self):
        return score # I don't know how you're doing this so...
    def win(self,player):
        print("{} wins!".format(player.name))
    def run(self):
        self.running = True
        while self.running:
            for player in self.players:
                roll = dice_rolling()
                player.score += scoring()
                if player.score >= 100:
                    self.running = False
                    win(player)

Game().run()

Answer 2

您的代码可能无法正常工作，因为相反为此1分配player_turn：

player_turn == 1

应该是这样的：

player_turn = 1

Answer 3

你可以尝试使用列表结构。

如果有4名球员，那将会是这样的：

turns = [0,1,2,3,4,0,1,2,3,4]

#this would add another turn for player 0, to remove you just use del
turns.append(0)


#This would remove a winner from your turn stack while preserving the order
for i in turns:
    if i ==4:
        del i

#You could also use a dictionary if you don't like list indicies or numbers:
Players = {"blue":3, red":4, "green":2, "orange":1}

turn = [4,2,1,3,4,2,1,3]

#If there is also a maximum number of turns, you can have that hard coded also:
for i in range(max):
    turn.append(1)
    turn.append(2)
    turn.append(3)
    turn.append(4)

说实话，我并不真正理解你的问题，但希望这可能完全或部分地回答了这个问题。

如何为多个玩家创建循环转？

3 个答案: